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2 years ago

Someone please help me:/

Mathematics

2 answers:

Marrrta [24]2 years ago

7 0

Answer: P

Step-by-step explanation:

brilliants [131]2 years ago

4 0

Answer:

Step-by-step explanation:

The sqrt of 8 is 2.82842712475 and Q is the closest to that.

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PLS HELP!! :)) Find the volume......

OLEGan [10]

Answer:

19 + 14 + 10 = 43

Step-by-step explanation:

7 0

2 years ago

Sofia wrote three numbers between 0.77 and 0.78 what numbers Sofia

Ostrovityanka [42]

Answer:

0.771, 0.772, 0.773

Step-by-step explanation:

three numbers between 0.77 and 0.78

0.77 = 0.770

and

0.78 = 0.780

So,

0.770, 0.771, 0.772, 0.773, 0.780

= 0.77, 0.771, 0.772, 0.773, 0.78

5 0

2 years ago

Mr. Morales owns a warehouse that is 56,000 cubic feet. He wants to build an addition that will increase the size of the warehou

Gennadij [26K]

Answer:

62,160 cubic feet

Step-by-step explanation:

To solve this problem, we can use a percentage formula as shown below:

$P(1+r)$

P = initial value

r = rate

Now lets plug in the values given in the question:

$56,000(1+.11) =$ 62,160

This means that the volume of the warehouse after the addition will be 62,160 cubic feet.

5 0

3 years ago

What is the total cost of 0.5 pound of peaches selling for $0.80 per pound and 0.7 pound of oranges selling for $0.90 pet pound?

kari74 [83]

The total cost for peaches is $0.40 you get that by (0.5)(0.80) as for oranges (0.7)(.90)=$0.63 so $0.40+$0.63=$1.03

3 0

2 years ago

Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method

antoniya [11.8K]

Answer:

The estimate is $- 0.0265\le K \le 0.0465$

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

The number of microchips broken in method B is $n_2 = 400$

The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

$p_1 = \frac{32}{400}$

$p_1 = 0.08$

The proportion of the faulty to the total breaks in method B is

$p_2 = \frac{28}{400}$

$p_2 = 0.07$

For this estimation the standard error is

$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

substituting values

$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

$SE = 0.0186$

The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

substituting values

$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

$K = - 0.0265 \ or \ K = 0.0465$

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

$- 0.0265\le K \le 0.0465$

3 0

2 years ago