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Svetradugi [14.3K]
3 years ago
11

What is the quotient of -1/8 and - 1/3

Mathematics
1 answer:
eimsori [14]3 years ago
3 0

Answer:

Step-by-step explanation:

(-1/8)/(-1/3) = (-1/8)×(3/-1) = (-1)(3)/(8)(-1) = -3/-8 = 3/8

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6-√8 divide √2-1
agasfer [191]

Answer:

4\sqrt{2}  +2

Step-by-step explanation:

\frac{6-\sqrt{8}}{\sqrt{2}-1}

=\frac{6-\sqrt{8}}{\sqrt{2}-1} ×\frac{\sqrt{2}+1}{\sqrt{2}+1}

=\frac{(6-\sqrt{8})(\sqrt{2}+1)}{2-1}

=6\sqrt{2} + 6 -\sqrt{8}\sqrt{2} - \sqrt{8}

=6\sqrt{2} + 6 - 4 - \sqrt{8}

=6\sqrt{2} + 2 - \sqrt{8}

=6\sqrt{2} + 2 - 2

=4\sqrt{2}  +2

for \sqrt{8} = 2\sqrt{2} ,

\sqrt{8} = \sqrt{2*2*2}

     = (\sqrt{2})^2 × \sqrt{2}

     =2 ×\sqrt{2}

5 0
3 years ago
Explain why a graph that fails the vertical-line test does not represent a function. Be sure to use the definition of a function
ArbitrLikvidat [17]

Explanation:

A function is a relationship where any one x-value/input only has <u>one </u>corresponding y-value/output. (note: a y-value can have multiple x-values).

> This can be called "assigning one y-value to every x element".

The vertical line test places a line that would connect all y-values of an x-value (that is, if it were to have multiple y-values). If multiple points can be found along the vertical line, it is, therefore, by the definition of a function, not a function. (Because an x-value will have more than one y-value).

So, a graph that fails the vertical-line test does not represent a function because an x-value will correspond with more than one y-value.

hope this helps!!

4 0
2 years ago
Is 1.888... an irrational number? (i have a 1 in math :C)
Ipatiy [6.2K]
No, 1.888 is a rational number.
3 0
3 years ago
Omar has 1/4 of a pizza. He wants to eat 2/3 of this amount. How much of the pizza will omar eat ?
Talja [164]
5/12 uuuuurrr welcome

8 0
3 years ago
A marble is randomly selected from a bag. The probability of selecting a marble with dots on it is 0.2. The probability of selec
marin [14]

Answer:

0.5

Step-by-step explanation:

Let D be the event of selecting a marble with dots.

Let P be the event of selecting a purple marble.

The probability of selecting a marble with dots, P(D)=0.2

The probability of selecting a marble that is both purple and has dots, P(D \cap P)=0.1

We want to determine the probability of selecting a purple marble given that the marble has dots on it, P(P|D)

By the definition of conditional probability:

P(P|D)= \dfrac{P(P \cap D)}{P(D)} \\= \dfrac{0.1}{0.2}\\ =0.5

The probability of selecting a purple marble given that the marble has dots on it is 0.5.

4 0
3 years ago
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