Since there is no additional information, let's assume that the fruit punch is made using just three juice fruits, lemonade juice, cranberry juice and the rest is orange juice.

We can calculate the fraction of the orange juice using the following information:

$FruitPunch=\frac{1}{4}Lemonade+\frac{1}{12}Cranberry+Orange\\\\1cup=\frac{1}{4}cup+\frac{1}{12}cup+Orange\\\\1cup-(\frac{1}{4}cup+\frac{1}{12}cup)=Orange\\\\1cup-(\frac{12+4}{4*12})=Orange\\\\Orange=1cup-\frac{16}{48}cup=1cup-\frac{1}{3}cup=\frac{3-1}{3}cup=\frac{2}{3}cup$

Hence, we have that the fraction of the orange juice will be 2/3cup.

Have a nice day!

8 0

3 years ago

Please some one help me.

vagabundo [1.1K]

Answer:

-11

Step-by-step explanation:

You need to take the absolute value of 12-15 which would be 3. Then take -8-3 which would be -11

3 0

3 years ago

A magazine currently has 8700 subscribers for its online web version. It is adding members at the rate of R(t) = 190e0.03t subsc

aleksklad [387]

Number of subscriber the magazine will have after 3 years from now approximately be 8767

Solution:

Given that magazine currently has 8700 subscribers for its online web version

$\begin{array}{l}{\mathrm{R}(\mathrm{t})=190 \mathrm{e}^{0.03 \mathrm{t}} \text { subscribers/month }} \\\\ {\mathrm{S}(\mathrm{t})=\mathrm{e}^{-0.06 \mathrm{t}}}\end{array}$

After 3 years, time(t) = 36 month

Total number of subscribers after 3 years from now :

Substitute "t" = 36

$\begin{array}{l}{\mathrm{R}(36)=190 \mathrm{e}^{0.03 \times(36)}=190 \times(2.944)} \\\\ {\mathrm{R}(36) \approx 560} \\\\ {\mathrm{S}(36)=\mathrm{e}^{-0.06 \times(36)}=0.12}\end{array}$

Subscribers remaining = 0.12 x 560 = 67.2

The magazine currently has 8700 subscribers

Added Subscriber = 8700 + 560 = 9260

Remaining Subscriber = 8700 + 67.2 = 8767.2

Therefore number of subscriber the magazine will have after 3 years from now approximately be 8767

7 0

3 years ago