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Galina-37 [17]
3 years ago
11

BEST ANSWER GETS BRAINLIEST!!! PLEASE HELP

Mathematics
2 answers:
VikaD [51]3 years ago
7 0
Answer would be B
Becuase how many baseball he will buy would be multiply to the cost
9.95+2.99z
Harman [31]3 years ago
5 0
9.95 + 2.99z <=========
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Can anyone solve this please asap​
Reika [66]

Answer:

<h2>= 1.268</h2>

Step-by-step explanation:

= (3 + √3) (2 - √3)

= 6 - 3√3 + 2√3 - 3

= 3 - 3√3 + 2√3

= 3 - √3 (3 - 2)

= 3 - √3

= 3 - 1.732 ...... (√3 = 1.732)

= 1.268

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3 years ago
Solve each of the following equations
gladu [14]
Look at the photo I’ve attached

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3 years ago
How do u do this? PLz show work!!!!
marissa [1.9K]
N:7=x remainder 2
⇒ n= 7*x +2
 
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4 0
3 years ago
Read 2 more answers
Determine whether each of these sets is nite, countably in nite, or uncount- able. For those that are countably in nite, exhibit
ira [324]

Answer:

Integers that are divisible by 7 are countably infinite

The set are {7, 14, 21, 28, 35, 42, 49,......

Integers that are divisible by 10 are countably infinite

The set are {10, 20, 30, 40, 50, 60, 70,........

Also for the negative integers divisible by 7 or 10{.......,-49, -42, -35, -28, -21, -14, -7} or {........,-70, -60, -50, -40, -30, -20, -10} are countably infinite

Step-by-step explanation:

See the set of integers divisible by 7 or 10,

{7, 14, 21, 28, 35, 42, 49,........} Or

{10, 20, 30, 40, 50, 60, 70,.......}

Can be map one-to-one to {1,2,3,4,5,6,7,...... The set of natural numbers or positive Integers.

So also, it is applicable in negative integers divisible by 7 or 10.

Therefore, they are countably infinite

A set is uncountable if it contains so many elements that they cannot be put in one-to-one correspondence with the set of natural numbers(Positive Integers). In other words, there is no way that one can count off all elements in the set in such a way that, even though the counting will take forever, you will get to any particular element in a finite amount of time.

WHILE

A set is countable or countably finite if it contains so many elements that they CAN be put in one-to-one correspondence with the set of natural numbers(Positive Integers)

3 0
3 years ago
Who can help me with this I’ll mark u as brainliest
Vikentia [17]

Answer:

The answer is D

Step-by-step explanation:

Crown me?

5 0
3 years ago
Read 2 more answers
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