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3 years ago

Evaluate the discriminant for each equation, then use it to determine the nature of the roots for each quadratic equations

1 answer:

4 0

The discriminant of a quadratic equation is a parameter that is used to determine the nature of the roots of the equation. The discriminant can be determined by b2- 4ac. The standard form of quadratic equation is ax2 + bx + c = 0. Upon substitution, we can easily determine the discriminant. If disc. is zero, the roots are equal; if <0, then the roots are positive and non-identical; if <0, the roots are negative and imaginary.

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choose the equation below that represents the line passing through the point (−2, −3) with a slope of −6. y 3 = −6(x 2) y 2 = 6(

pishuonlain [190]

Line passing through point (-2, -3) with a slope of -6 is (y - (-3)) = -6(x - (-2)) => y + 3 = -6(x + 2)

7 0

3 years ago

Write the equation of the line that passes through the points (0,8) and (-1,-4).

Anettt [7]

Step-by-step:

Use slope formula to find the slope. (y - y)/(x - x)

Make sure the x and y in front of the minus is a pair that goes together, as well as the x and y behind the minus sign. So

8 - -4 goes on top, that's 12

0 - -1 goes under, thats 1

12/1 is the slope which is just 12. Use either point to fill in the second x and the second y in the point-slope equation. m is the slope.

y - y = m(x - x)

y - 8 = 12(x - 0)

y - 8 = 12x

5 0

3 years ago

A rectangle has an area of 0.24 of a square. What are some possibility for the length and width of the rectangle? Tell why

VLD [36.1K]

Answer:

<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>

Step-by-step explanation:

Given that the area is 0.24 square meter

The area of a rectangle is given by

$Area=length\times width$ square units

Let x be the length and y be the width.

Since the area is 0.24 square meter, we have the equation:

$Area=x\times y = 0.24$ , with x and y measures in meters

If we want to know some possibilities of x and y, we can assume a value for one of them, and then calculate the other one using the equation.

Now choosing some values for "x", we have:

Put x = 1

$1\times y = 0.24$

∴ y = 0.24

Now put x = 0.5 we get

$0.5\times y = 0.24$

∴ y = 0.48

Put x = 0.25

$0.25\times y = 0.24$

∴ y = 0.96

Put x = 2

$2\times y = 0.24$

∴ y = 0.12

8 0

3 years ago

Read 2 more answers

A simple random sample of size nequals15 is drawn from a population that is normally distributed. The sample mean is found to be

Bond [772]

Answer with explanation:

To test the Significance of the population which is Normally Distributed we will use the following Formula Called Z test

$z=\frac{\Bar X - \mu}{\frac{\sigma}{n}}$

$\Bar X =31.1\\\\ \sigma=6.3\\\\ \mu=25\\\\n=15\\\\z=\frac{31.1-25}{\frac{6.3}{\sqrt{15}}}\\\\z=\frac{6.1\times\sqrt{15}}{6.3}\\\\z=\frac{6.1 \times 3.88}{6.3}\\\\z=3.756$

→p(Probability) Value when ,z=3.756 is equal to= 0.99992=0.9999

⇒Significance Level (α)=0.01

We will do Hypothesis testing to check whether population mean is different from 25 at the alpha equals 0.01 level of significance.

→0.9999 > 0.01

→p value > α

With a z value of 3.75, it is only 3.75% chance that ,mean will be different from 25.

So,we conclude that results are not significant.So,at 0.01 level of significance population mean will not be different from 25.

3 0

3 years ago

On a winter morning, the temperature before sunrise was 11 degrees. The temperature then rose by 1/2 degree each hour for 7 hour

Arada [10]

Answer:

7.75 F

Step-by-step explanation:

you will do 7/2 *

convert 2.25 to imporper fraction

multiply the denomintor

7 0

3 years ago