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TiliK225 [7]
3 years ago
5

An arithmetic sequence is given below.

Mathematics
1 answer:
Mashcka [7]3 years ago
3 0
Given that a_1=24 and a_2=17, if a_n is an arithmetic sequence, then the common difference between successive terms is d=a_2-a_1=17-24=-7.

You then have

a_2=a_1+d
\implies a_3=a_2+d=a_1+2d
\implies a_4=a_3+d=a_1+3d
\implies \cdots\implies a_n=a_{n-1}+d=\cdots=a_1+(n-1)d

So the explicit formula for the nth term is

a_n=24-7(n-1)
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Explain how you can determine that the following system has one unique solution – without actually solving the system.
MakcuM [25]

Answer:

Step-by-step explanation:

Well, first you'd have to get the equations in slope-intercept form in order to make it easier for you to see it in the bigger picture. 2x+y=4 would be y= 2x-4, and the other equation would be y= x-3. If you were to solve it, there would be one solution since the y's cancel out. If you graphed it, there would be a point of intersection, unlike when the lines are parallel if there's 0 solutions or only one line's there if there's infinitely many solutions.

7 0
4 years ago
The ratio of blue marbles to green marbles in the box is 13 to 24.
Papessa [141]

Answer:

37

Step-by-step explanation:

13 blue

24 green

4 0
3 years ago
What is the reciprocal of the interger 67 ?
boyakko [2]
1/67 maybe -------------------
4 0
4 years ago
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A cow can drink up to 35 gallons of water in a day. How many 8 ounce glasses could a cow drink in a day?
Sladkaya [172]

Answer:

if 128 ounces is one gallon then the cow can drink up to 4480 ounces , which is the same as 35 gallons

Step-by-step explanation:

vote and like if it the answer

3 0
3 years ago
Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}
Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

f(A) = \{x^2  \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2  \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4]  = f(A \cap B)\\

Therefore it is true for intersection. Now for union, we have that

A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]

Therefore, for this case, it would be true that f(A\cup B) = f(A)\cup f(B).

(b)

1 is not a set.

(c)

To begin with  

A\cap B \subset A,B

Therefore

g(A\cap B) \subset g(A) \cap g(B)

Now, given an element of g(A) \cap g(B) it will belong to both sets, therefore it also belongs to g(A\cap B), and you would have that

g(A)\cap g(B) \subset  g(A \cap B), therefore  g(A)\cap g(B)  =  g(A \cap B).

(d)

To begin with A,B  \subset A \cup B, therefore

g(A) \cup g(b) \subset g(A\cup B)

7 0
4 years ago
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