Given the equation, D = if D = and = m + 3, then m = A.) - 18 B.) 18 C.) 15 <br>please hurry !

If the probability of a new employee in a fast-food chain still being with the company at the end of the year is 0. 5, what is t

Mazyrski [523]

Using binomial distribution, the probability of

a. 5 will still be with the company after 1 year is 28%.

b. at most 6 will still be with the company after 1 year is 89%.

The probability of a new employee in a fast-food chain still being with the company at the end of the year is given to be 0.6, which can be taken as the success of the experiment, p.

We are finding probability for people, thus, our sample size, n = 8.

Thus, we can show the given experiment a binomial distribution, with n = 8, and p = 0.6.

(i) We are asked for the probability that 5 will still be with the company.

Thus, we take x = 5.

P(X = 5) = (8C5)(0.6⁵)((1 - 0.6)⁸⁻⁵),

or, P(X = 5) = (56)(0.07776)(0.064),

or, P(X = 5) = 0.27869184 ≈ 0.28 or 28%.

(ii) We are asked for the probability that at most 6 will still be with the company.

Thus, our x = 6, and we need to take all values below it also.

P(X ≤ 6)

= 1 - P(X > 6)

= 1 - P(X = 7) - P(X = 8)

= 1 - (8C7)(0.6)⁷((1 - 0.6)⁸⁻⁷) - (8C8)(0.6)⁸((1 - 0.6)⁸⁻⁸)

= 1 - 8*0.0279936*0.4 - 1*0.01679616*1

= 1 - 0.08957952 - 0.01679616

= 0.89362432 ≈ 0.89 or 89%.

Learn more about the binomial distribution at

brainly.com/question/24756209

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The provided question is incomplete. The complete question is:

If the probability of new employee in a fast-food chain still being with the company at the end of 1 year is 0.6, what is the probability that out of 8 newly hired people,

a. 5 will still be with the company after 1 year?

b. at most 6 will still be with the company after 1 year?

3 0

2 years ago

Jane travels7 mph less than2 times as fast as Mike. Starting at the same point and traveling in the same direction, they are198

Sphinxa [80]

Let:

Vj = Speed of jane

Vm = Speed of mike

d = distance

t = time

Jane travels 7 mph less than 2 times as fast as Mike, therefore:

Vj = 2Vm - 7

Remeber:

distance = speed*time

Distance traveled by mike:

d=Vm*t = Vm*6

Distance traveled by jane:

d + 198 = Vj*6

where:

Vj = 2Vm - 7

d + 198 = (2Vm-7)*6

Now, let:

d=Vm*6 (1)

d + 198 = (2Vm-7)*6 (2)

Replace (1) into (2)

6Vm + 198 = 12Vm - 42

Subtract 6Vm from both sides:

6Vm + 198 - 6Vm = 12Vm - 42 - 6Vm

198 = 6Vm - 42

Add 42 to both sides:

198 + 42 = 6Vm - 42 + 42

240 = 6Vm

Divide both sides by 6:

240/6 = 6Vm/6

40 = Vm

Vm = 40mph

Replace Vm into this equation Vj = 2Vm - 7 :

Vj = 2(40) - 7 = 80 - 7 = 73mph

4 0

1 year ago

Daniel clearly chose a unit of measure (miles) that was too big for the construction work he was doing. Tape measures do not hav

Leokris [45]

Answer:

personally i would use a.

Step-by-step explanation:

this is my answer and opinion btw

5 0

3 years ago

A builder drives 9.5 miles round-trip to and from a construction site. If 68 days

viva [34]

Answer:

646 miles

Step-by-step explanation:

3 0

3 years ago

Which is the better deal?

prisoha [69]

Answer: 5 feet of wood for 2.23

because the unit rate for each foot of wood is .45 compared to getting 6 feet for 2.95. 2.23 plus .43 (the cost for one foot) would be 2.63 making the wood much cheaper than the 6 foot option.

6 0

3 years ago

Given the equation, D = if D = and = m + 3, then m = A.) - 18 B.) 18 C.) 15 please hurry !