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Fudgin [204]
2 years ago
13

There are 9 lions there are fewer cubs than lions how many fewer cubs are there ?

Mathematics
1 answer:
Aleks04 [339]2 years ago
7 0

Number of cubs are less than 9.

In Algebra, an inequality is a mathematical statement that uses the inequality symbol to illustrate the relationship between two expressions. An inequality symbol has non-equal expressions on both sides. It indicates that the phrase on the left should be bigger or smaller than the expression on the right, or vice versa. Literal inequalities are relationships between two algebraic expressions that are expressed using the inequality symbols.

NO. OF LIONS = 9

Cubs are fewer than 9

To learn more about inequality, refer to brainly.com/question/25275758

#SPJ9

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Which of the following scenarios represents<br>the smallest percent change?​
mestny [16]

Answer:

A baby that weighed 6 1/4 pounds at birth now weighs 8 pounds.

Step-by-step explanation:

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4 years ago
How can you solve for x?
Ierofanga [76]

Answer:

        x = 55°

Step-by-step explanation:

From given figure  we have

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2 years ago
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(x2 + 4)(x2 - 4) please help
VikaD [51]

(x^{2} + 4)(x^{2} - 4)

To solve this question you must FOIL (First, Outside, Inside, Last) like so

First:

(x^2 + 4)(x^2 - 4)

x^2 * x^2

x^4

Outside:

(x^2 + 4)(x^2 - 4)

x^2 * -4

-4x^2

Inside:

(x^2 + 4)(x^2 - 4)

4 * x^2

4x^2

Last:

(x^2 + 4)(x^2 - 4)

4 * -4

-16

Now combine all the products of the FOIL together like so...

x^4 - 4x^2 +4x^2 - 16

Combine like terms:

x^4 - 4x^2 +4x^2 - 16

- 4x^2 +4x^2 = 0

x^4 - 16 <<<This is your answer

Hope this helped!

~Just a girl in love with Shawn Mendes

4 0
3 years ago
Hey <br>what is 6/5 ÷ 10/7 in the simplest form possible​
d1i1m1o1n [39]

Exact Form: 21/25

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5 0
3 years ago
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Find the mass of the triangular region with vertices (0, 0), (3, 0), and (0, 1), with density function ρ(x,y)=x2+y2.
ololo11 [35]

Since density is the ratio of mass to (in this case) area, we can find the mass of the triangular region \mathcal T by computing the double integral of the density function over \mathcal T:

\mathrm{mass}=\displaystyle\iint_{\mathcal T}\rho(x,y)\,\mathrm dx\,\mathrm dy

The boundary of \mathcal T is determined by a set of lines in the x,y plane. One way to describe the region \mathcal T is by the set of points,

\mathcal T=\left\{(x,y)\mid0\le x\le 3\,\land\,0\le y\le1-\dfrac x3\right\}

So the mass is

\mathrm{mass}=\displaystyle\int_{x=0}^{x=3}\int_{y=0}^{y=1-x/3}(x^2+y^2)\,\mathrm dy\,\mathrm dx

=\displaystyle\int_{x=0}^{x=3}\left(x^2y+\frac{y^3}3\right)\bigg|_{y=0}^{y=1-x/3}\,\mathrm dx

=\displaystyle\int_{x=0}^{x=3}\left(x^2\left(1-\frac x3\right)+\frac{\left(1-\frac x3\right)^3}3\right)\,\mathrm dx

=\displaystyle\frac1{81}\int_0^3(27-27x+90x^2-28x^3)\,\mathrm dx=\frac52

6 0
3 years ago
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