27. 8 minus the product of 9 and r

Reflect the figure over the line y-2. Please help

Lana71 [14]

(5,0) (9,6) (7,7) (2,7)

8 0

3 years ago

Whats x^2-2x-2 akjdcpiwhbfcnkluje

BaLLatris [955]

Answer:

Step-by-step explanation:

1 In general, given a{x}^{2}+bx+cax

2

+bx+c, the factored form is:

a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a

2a

−b+√

b

2

−4ac

)(x−

2a

−b−√

b

2

−4ac

)

2 In this case, a=1a=1, b=-2b=−2 and c=-2c=−2.

(x-\frac{2+\sqrt{{(-2)}^{2}-4\times -2}}{2})(x-\frac{2-\sqrt{{(-2)}^{2}-4\times -2}}{2})(x−

2

2+√

(−2)

2

−4×−2

)(x−

2

2−√

(−2)

2

−4×−2

)

3 Simplify.

(x-\frac{2+2\sqrt{3}}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

2

2+2√

3

)(x−

2

2−2√

3

)

4 Factor out the common term 22.

(x-\frac{2(1+\sqrt{3})}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

2

2(1+√

3

)

)(x−

2

2−2√

3

)

5 Cancel 22.

(x-(1+\sqrt{3}))(x-\frac{2-2\sqrt{3}}{2})(x−(1+√

3

))(x−

2

2−2√

3

)

6 Simplify brackets.

(x-1-\sqrt{3})(x-\frac{2-2\sqrt{3}}{2})(x−1−√

3

)(x−

2

2−2√

3

)

7 Factor out the common term 22.

(x-1-\sqrt{3})(x-\frac{2(1-\sqrt{3})}{2})(x−1−√

3

)(x−

2

2(1−√

3

)

8 Cancel 22.

(x-1-\sqrt{3})(x-(1-\sqrt{3}))(x−1−√

3

)(x−(1−√

3

))

9 Simplify brackets.

(x-1-\sqrt{3})(x-1+\sqrt{3})(x−1−√

3

)(x−1+√

3

)

7 0

3 years ago

Read 2 more answers

In the diagram below, assume that all points are given in rectangular coordinates. Determine the polar coordinates for each poin

Korolek [52]

Step-by-step explanation:

We have cartisean points. We are trying to find polar points.

We can find r by applying the pythagorean theorem to the x value and y values.

$r {}^{2} = {x}^{2} + {y}^{2}$

And to find theta, notice how a right triangle is created if we draw the base(the x value) and the height(y value). We also just found our r( hypotenuse) so ignore that. We know the opposite side and the adjacent side originally. so we can use the tangent function.

$\tan(x) = \frac{y}{x}$