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MA_775_DIABLO [31]
3 years ago
13

27. 8 minus the product of 9 and r

Mathematics
1 answer:
Tems11 [23]3 years ago
6 0
8-9r is the answer to this
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(5,0) (9,6) (7,7) (2,7)
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3 years ago
Whats x^2-2x-2<br><br><br><br><br><br><br><br><br><br><br> akjdcpiwhbfcnkluje
BaLLatris [955]

Answer:

Step-by-step explanation:

1 In general, given a{x}^{2}+bx+cax

​2

​​ +bx+c, the factored form is:

a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a

​2a

​

​−b+√

​b

​2

​​ −4ac

​

​​

​​ )(x−

​2a

​

​−b−√

​b

​2

​​ −4ac

​

​​

​​ )

2 In this case, a=1a=1, b=-2b=−2 and c=-2c=−2.

(x-\frac{2+\sqrt{{(-2)}^{2}-4\times -2}}{2})(x-\frac{2-\sqrt{{(-2)}^{2}-4\times -2}}{2})(x−

​2

​

​2+√

​(−2)

​2

​​ −4×−2

​

​​

​​ )(x−

​2

​

​2−√

​(−2)

​2

​​ −4×−2

​

​​

​​ )

3 Simplify.

(x-\frac{2+2\sqrt{3}}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

​2

​

​2+2√

​3

​

​​

​​ )(x−

​2

​

​2−2√

​3

​

​​

​​ )

4 Factor out the common term 22.

(x-\frac{2(1+\sqrt{3})}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

​2

​

​2(1+√

​3

​

​​ )

​​ )(x−

​2

​

​2−2√

​3

​

​​

​​ )

5 Cancel 22.

(x-(1+\sqrt{3}))(x-\frac{2-2\sqrt{3}}{2})(x−(1+√

​3

​

​​ ))(x−

​2

​

​2−2√

​3

​

​​

​​ )

6 Simplify brackets.

(x-1-\sqrt{3})(x-\frac{2-2\sqrt{3}}{2})(x−1−√

​3

​

​​ )(x−

​2

​

​2−2√

​3

​

​​

​​ )

7 Factor out the common term 22.

(x-1-\sqrt{3})(x-\frac{2(1-\sqrt{3})}{2})(x−1−√

​3

​

​​ )(x−

​2

​

​2(1−√

​3

​

​​ )

​​ )

8 Cancel 22.

(x-1-\sqrt{3})(x-(1-\sqrt{3}))(x−1−√

​3

​

​​ )(x−(1−√

​3

​

​​ ))

9 Simplify brackets.

(x-1-\sqrt{3})(x-1+\sqrt{3})(x−1−√

​3

​

​​ )(x−1+√

​3

​

​​ )

7 0
3 years ago
Read 2 more answers
In the diagram below, assume that all points are given in rectangular coordinates. Determine the polar coordinates for each poin
Korolek [52]

Step-by-step explanation:

We have cartisean points. We are trying to find polar points.

We can find r by applying the pythagorean theorem to the x value and y values.

r  {}^{2} =  {x}^{2}  +  {y}^{2}

And to find theta, notice how a right triangle is created if we draw the base(the x value) and the height(y value). We also just found our r( hypotenuse) so ignore that. We know the opposite side and the adjacent side originally. so we can use the tangent function.

\tan(x)  =  \frac{y}{x}

Remeber since we are trying to find the angle measure, use inverse tan function

\tan {}^{ - 1} ( \frac{y}{x} )  =

Answers For 2,5

{2}^{2}  +  {5}^{2}  =  \sqrt{29}  = 5.4

So r=sqr root of 29

\tan {}^{ - 1} ( \frac{5}{2} )  = 68

So the answer is (sqr root of 29,68).

For -3,3

{ -3 }^{2}  +  {3}^{2}  =  \sqrt{18}  = 3 \sqrt{2}

\tan {}^{ - 1} ( \frac{3}{ - 3} )  =  - 45

Use the identity

\tan(x)  =  \tan(x + \pi)

So that means

\tan(x)  = 135

So our points are

(3 times sqr root of 2, 135)

For 5,-3.5

{5}^{2}  +  {3.5}^{2}  =  \sqrt{37.25}

\tan {}^{ - 1} ( \frac{ - 3.5}{ - 5} )  = 35

So our points are (sqr root of 37.25, 35)

For (0,-5.4)

{0}^{2}  +  { - 5.4}^{2}  = \sqrt{}  29.16 = 5.4

So r=5.4

\tan {}^{ - 1}  (0)  = undefined

So our points are (5.4, undefined)

4 0
3 years ago
X + 4y = -8 x-4y=-8 elimination
Juli2301 [7.4K]

Steps :-

■ Eliminate the equations (subtract them). You'll get the value of 1 variable.

■ Then substitute in another equation to get the value of the other variable.

Answer :-

■ x = -8 & y = 0

See the attachment for the steps.

________

Hope it helps ⚜

6 0
3 years ago
When she first purchased it, Soledad’s computer had 400 GB of hard drive space. After six months, there were only 282 GB availab
lesya [120]
282+x=400     282-282+x=400-282    x= 118  118 gb used in the first six months 
8 0
3 years ago
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