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sergey [27]
4 years ago
7

Solve for x. -2(3x – 4) – X – 3 = 33

Mathematics
1 answer:
Inessa [10]4 years ago
3 0

Answer:

- 4

Step-by-step explanation:

Step 1:

- 2 ( 3x - 4 ) - x - 3 = 33

Step 2:

- 6x + 8 - x - 3 = 33

Step 3:

- 7x + 5 = 33

Step 4:

- 7x = 28

Step 5:

- 28 = 7x

Answer:

- 4 = x

Hope This Helps :)

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A ball is thrown from an initial height of 4 feet with an initial upward velocity of 17ft/s. The ball's height h (in feet) after
iVinArrow [24]
Use quadratic formula 
8= 4 +17t -16t^2
16t^2 - 17 t + 4
answers (17 + square root (33)) /32 and  (17 - square root (33)) /32
4 0
4 years ago
HURRY PLEASE <br><br> What is the solution of the system 4x+3y=6 2x+2y=5
jolli1 [7]
The first given equation is:
4x + 3y = 6
which can be rewritten as:
2(2x) + 3y = 6 .............> equation I

The second given equation is:
2x + 2y = 5
which can be rewritten as:
2x = 5 - 2y ........> equation II

Substitute with equation II in equation I to get the value of y as follows:
2(5-2y) + 3y = 6
10 - 4y + 3y = 6
-y = 6-10 = -4
y = 4

Substitute with the y in equation II to get x as follows:
2x = 5 - 2y
2x = 5 - 2(4)
2x = 5 - 8 = -3
x = -3/2

From the above calculations:
x = -3/2
y = 4
7 0
4 years ago
Read 2 more answers
True or false please help
Snowcat [4.5K]
I believe it’s true not 100% sure
5 0
4 years ago
Round your answer to the nearest percent.
emmainna [20.7K]

Answer:

Step-by-step explanation:

Givens

Number not using given app = 71

Total number of students  = 219

% = ?

Solution

P(~given app) = 71 / 219

P(~given app)  = 0.324

% = 0.324 * 100  = 32.4%

Answer

32.4% do not use Given App

4 0
2 years ago
Please hepl with math
Ivenika [448]

Answer:

\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}

Step-by-step explanation:

We are given the expression to be simplified:

\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}}

Let us take common a term with a power of 5 from the numerator and the denominator of the given expression.

We know that:

a^{p+q} = a^p \times a^q

Let us use it to solve the powers of 5 in the given expression.

\therefore we can write:

5^{n+2} = 5^{n+1}\times 5= 5^n\times 5^{2}

5^{n+1} = 5^n\times 5

The given expression becomes:

\dfrac{5^{n+1} \times 5-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n}\times 5}

Taking common 5^{n+1} from the numerator and

Taking common 5^{n} from the denominator

\Rightarrow \dfrac{5^{n+1} (5-6)} {5^{n}(13-2\times5)}\\\Rightarrow \dfrac{5^{n+1} (-1)} {5^{n}(13-10)}\\\Rightarrow -\dfrac{5^{n+1}} {5^{n}\times3}\\\Rightarrow -\dfrac{5^{n}\times 5} {5^{n}\times3}\\\Rightarrow -\dfrac{5}{3}

\therefore The answer is:

\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}

6 0
3 years ago
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