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Yakvenalex [24]
3 years ago
9

All of the following are correct except _____. 3 2 + 5 - 2 = 12 3 2 - 5 + 2 = 6 3 2 5 + 2 = 47 3 2 + 5 2 = 28

Mathematics
1 answer:
zepelin [54]3 years ago
5 0

Answer:

269

Step-by-step explanation:

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The 24-hour time is 14:00. Find the equivalent 12-hour time. Show all work.
Alexxandr [17]
It's 2:00 pm.
12:00 is noon, and since 14 is 2 hours more, I just figured it out. Here are some other answers. 

13:00- 1 pm
14:00- 2 pm
15:00- 3 pm
16:00- 4 pm
17:00- 5 pm
18:00- 6 pm
19:00 7 pm
20:00 8 pm
21:00 9 pm
22:00- 10 pm
23:00 is 11 pm
24:00 is midnight
Any of those with numbers after that is the same hour with different minutes, for example 20:22  is 8:22 pm. Hope I helped. 

7 0
3 years ago
What is equivalent to 45/75?
dexar [7]
The answer is 0.6

Hope that’s helps
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3 years ago
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Ruben bought 6 new books for his collection by 12% How many books did he have before the purchase
lilavasa [31]
He had 50 books before 
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2 years ago
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Mara carried water bottles to the field to share with her team at halftime. The water bottles weighed a total of 60x^2 + 48x + 2
VLD [36.1K]

Answer:

b)\: 12(5x^2+4x+2)

Step-by-step explanation:

The given expression for water bottles is

60x^2+48x+24.


The highest common factor of all the terms of this expression is 12.


We now factor to obtain;

12(5x^2+4x+2)

Hence the the factorization that represents the number of water bottles and the weight of each bottle is the one in option B.

The correct answer is B


We therefore factor to obtain,


3 0
3 years ago
At carl's combine diner, there are three size of coffee drinks regular (300ml), large (500ml) and extra large (800mL), and they
MariettaO [177]

Answer:

The number of regular, large, and extra-large drinks are 12, 15, and 10 respectively.

Step-by-step explanation:

Given that the cost for regular coffee drinks (300 ml)=$2.25

The cost for large coffee drinks (500 ml)=$3.25

The cost for extra large coffee drinks (800 ml)=$5.75

Let p,q, and r be the number of regular, large, and extra-large coffee sold.

As the diner sold a total of 37 coffees, so

p+q+r=37

r=37-p-q...(i)

The volume of p regular coffee = 300p ml

The volume of q  large coffee = 500q ml

The volume of r extra-large coffee = 800r ml

As the total volume of coffee sold was 19,100mi, so

300p+500q+800r=19100

By using equation (i)

300p+500q+800(37-p-q)=19100

300p+500q+800 x 37 - 800p - 800q=19100

-500p-300q=19100-29600

500p+300q=10500

500p=10500-300q

p=21-0.6q...(ii)

Now, the cost of p regular coffee=$2.25p

The cost of q large coffee=$3.25q

The cost of r extra-large coffee=$5.75r

As the amount of money made in coffee sales was $133.25, so

2.25p+3.25q+5.75r=133.25

By using equations (1)  we have

2.25p+3.25q+5.75(37-p-q)=133.25

2.25p+3.25q+212.75-5.75p-5.75q=133.25

3.50p+2.50q=79.5

From equation (ii)

3.5(21-0.6q)+2.50q=79.5

73.5-2.1q+2.5q=79.5

0.4q=79.5-73.5=6

q=6/0.4

q=15

From equation (ii)

p=21-0.6(15)

p=12

From equation (i)

r= 37-12-15

r=10

Hence, the number of regular, large, and extra-large drinks are 12, 15, and 10 respectively.

5 0
3 years ago
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