Answer:
0.0143
Step-by-step explanation:
In this question, we are asked to use the binomial distribution to calculate the probability that 10 or fewer passengers from a sample of MIT data project sample were on American airline flights.
We proceed as follows;
The probability that a passenger was an American flight is 15.5%= 15.55/100 = 0.155
Let’s call this probability p
The probability that he/she isn’t on the flight, let’s call this q
q =1 - p= 0.845
Sample size, n = 155
P(X < A) = P(Z < (A - mean)/standard deviation)
Mean = np
= 125 x 0.155
= 19.375
Standard deviation = √npq
= √ (125 x 0.155x 0.845)
= 4.0462
P(10 or fewer passengers were on American Airline flights) = P(X \leq 10)
= P(Z < (10.5 - 19.375)/4.0462)
= P(Z < -2.19)
= 0.0143
Answer:
A. 18 3/4
Step-by-step explanation:
It is convenient to rearrange the sum to make it easier to compute:
7 3/4 + 4 3/4 + 6 1/4 = (7 3/4) +(4 +6) +(3/4 +1/4)
= 7 3/4 + 10 + 1
= 18 3/4
The farmer has 18 3/4 rows of radishes altogether.
Answer:
x = 2
Step-by-step explanation:
8(4-x) = 7x + 2
1) Distribute : 32 - 8x = 7x + 2
2) Subtract 32 : -8x = 7x - 30
3) Subtract 7x : -15x = -30
4) Divide 15 : x = 2 :)
225.45
+90.32
______
315.77
Nearest whole number
316
