Circumference of a circle =2πr
6.28=2πr
3.14=πr
3.14/π=r
3.14/3.14=r
<h2>therefore,r=1</h2>
Answer:
There are none.
Step-by-step explanation:
<u>No calculus involved:</u>
The line, in slope-intercept form, has equation
, ie is always decreasing (easy to spot applying the definition)
Meanwhile,
is always increasing over its domain.
At no point the tangent will be decreasing.
<u>Let's use calculus</u>
We are to solve the equation
which has no real solutions.
The correct term that would best complete the given statement above would be the word GUIDES. The guides <span>are two straight dotted lines, one horizontal and one vertical. This term "guide" is one of the terms used in Microsoft Powerpoint. Hope this is the answer that you are looking for. Thanks for posting!</span>
You have the length of the sides? If not: a and b is the length of the scratch, h is the height <span>This lateral surface area = 2ah+2bh=2h(a+b)</span>
Answer:
51 m^2
Step-by-step explanation:
The shaded area is the difference between the area of the overall figure and that of the rectangular cutout.
The applicable formulas are ...
area of a triangle:
A = (1/2)bh
area of a rectangle:
A = bh
area of a trapezoid:
A = (1/2)(b1 +b2)h
___
We note that the area of a triangle depends only on the length of its base and its height. The actual shape does not matter. Thus, we can shift the peak of the triangular portion of the shape (that portion above the top horizontal line) so that it lines up with one vertical side or the other of the figure. That makes the overall shape a trapezoid with bases 16 m and 10 m. The area of that trapezoid is then ...
A = (1/2)(16 m + 10 m)(5 m) = 65 m^2
The area of the white internal rectangle is ...
A = (2 m)(7 m) = 14 m^2
So, the shaded area is the difference:
65 m^2 -14 m^2 = 51 m^2 . . . . shaded area of the composite figure
_____
<em>Alternate approach</em>
Of course, you can also figure the area by adding the area of the triangular "roof" to the area of the larger rectangle, then subtracting the area of the smaller rectangle. Using the above formulas, that approach gives ...
(1/2)(5 m)(16 m - 10 m) + (5 m)(10 m) - (2 m)(7 m) = 15 m^2 + 50 m^2 -14 m^2
= 51 m^2