a teacher divides her class into groups and assigns each group a task of measuring the mass of the same object three times.the t
1 answer:
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Answer:
(a) Cgas = 0.125 kJ/k
(b) cgas = 0.25kJ/kg.K
(c) cm(gas) = 0.021kJ/mol.K
Explanation:
18.9 kJ is equal to the sum of the heat absorbed by the gas and the heat absorbed by the calorimeter.
Qcal + Qgas = 18.9 kJ [1]
We can calculate the heat absorbed using the following expression.
Q = C . ΔT
where,
C is the heat capacity
ΔT is the change in the temperature
<em>(a) What is the heat capacity of the sample?</em>
From [1],
Ccal . ΔT + Cgas . ΔT = 18.9 kJ
(2.22kJ/K) × 8.06 K + Cgas × 8.06 K = 18.9 kJ
Cgas = 0.125 kJ/k
<em>(b) If the sample has a mass of 0.5 kilograms, what is the specific heat capacity of the substance?</em>
We can calculate the specific heat capacity (c) using the following expression:
<em>(c) If the sample is Krypton, what is the molar heat capacity at constant volume of Krypton? The molar mass of Krypton is 83.8 grams/mole.</em>
The molar heat capacity is:
Answer : The limiting reactant is
Explanation : Given,
Mass of = 30.0 g
Mass of = 75.0 g
Molar mass of = 44 g/mole
Molar mass of = 32 g/mole
First we have to calculate the moles of and
.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 5 mole of react with 1 mole of
So, 2.34 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Therefore, the limiting reactant is
Answer:
Rate of reaction =
Rate of consumption of A =
Rate of consumption of B =
Rate of formation of D =
Explanation:
According to laws of mass action for the given reaction,
where, is rate of consumption of A,
is rate of consumption of B,
is rate of formation of C and
is rate of formation of D
Here
So, Rate of reaction =
Rate of formation of D =
Rate of consumption of A =
Rate of consumption of B =