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3 years ago

Name the most abundant isotope for these elements: Na = ____ P = _ Mn = ______

Chemistry

1 answer:

Elan Coil [88]3 years ago

5 0

Answer: 11, Na, 23, 100, −9.529 ... phosphorus, 15, P, 31, 100, −24.441 ... manganese, 25, Mn, 55, 100, −57.706.

Explanation: Make me Brainelist

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Name the cycloalkanes with molecular formula c6h12 that have a 3-membered ring and two substituents.

Tanzania [10]

Answer:

1-ethyl-2-methyl cyclopropane.

Explanation:

The structure of the molecule will be as shown in the attached image.

The molecular formula of the compound is C₆H₁₂.

It has 3 membered ring with 3 C atoms and two substituents one of them with one C atom (methyl) and the other with 2 C atoms (ethyl).

The ring consist of 3 C atoms, so its name is cyclo propane.

We numbering the atoms of the ring that give the ethyl substituent the low no. (1) and then methyl group take no. (2).

Thus, the name of the compound is 1-ethyl-2-methyl cyclopropane.

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3 years ago

Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find

FromTheMoon [43]

Answer: The concentration of $SO_4^{2-}$ at equilibrium is 0.00608 M

Explanation:

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

$H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)$

0.025 0.025 0.025

Equation for the second dissociation of sulfuric acid:

$HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)$

Initial: 0.025 0.025

At eqllm: 0.025-x 0.025+x x

The expression of second equilibrium constant equation follows:

$Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}$

We know that:

$Ka_2\text{ for }H_2SO_4=0.01$

Putting values in above equation, we get:

$0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608$

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of $SO_4^{2-}$ at equilibrium is 0.00608 M

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Answer:

the correct words to fill up the blank spaces are falls and money

Explanation:

.1. the expected return on money falls

.2. causing the demand for money to fall.

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Name the most abundant isotope for these elements: Na = ________ P = _______ Mn = ________

Name the most abundant isotope for these elements: Na = ____ P = _ Mn = ______