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3 years ago

How does the water in an estuary compare to the water in the open ocean?

Chemistry

1 answer:

sveta [45]3 years ago

5 0

Answer:

Estuaries have more concentrated nutrients and less concentrated salt.

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Are these two substances the same 1.96g/ml and 2.00g/ml

Zolol [24]

Answer:Water contains almost one thousand times more matter than the same volume of air would, therefore it is denser. ... If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass? ... Density is the mass per unit of volume of a substance. ... A block of platinum with a mass of 4,290 kilograms has a volume of .2 cubic meters.

Explanation:

4 0

3 years ago

Read 2 more answers

A quantity of 0.0250 mol of a gas initially at 0.050 L and 19.0°C undergoes a constant-temperature expansion against a constant

KiRa [710]

Answer:

$V_2=2.995L\\\\W=248.5J$

Explanation:

Hello,

In this case, for us to compute the final volume we apply the Boyle's law that analyzes the pressure-volume temperature as an inversely proportional relationship:

$P_1V_1=P_2V_2$

So we solve for $V_2$ by firstly computing the initial pressure:

$P_1=\frac{nRT}{V_1}=\frac{0.025mol*0.082\frac{atm*L}{mol*K}*(19+273.15)K}{0.050L} =11.98atm$

$V_2=\frac{P_1V_1}{P_2}=\frac{11.98atm*0.050L}{0.200atm}\\ \\V_2=2.995L$

Finally, we can compute the work by using the following formula:

$W=nRTln(\frac{V_2}{V_1} )=0.025mol*8.314\frac{J}{mol*K}*(19.0+273.15)K*ln(\frac{2.995L}{0.050L}) \\\\W=248.5J$

Best regards.

4 0

3 years ago

WHICH VIRAL REPRODUCTION CYCLE HAD THE VIRUS PUTTING ITS GENETIC MATERIAL INTO THE CELL

marissa [1.9K]

B lysosgenic hhhhhjjj had to make answer longer

7 0

3 years ago

Iodine-131 has a half-life of 8 days. If you have 8 g of I-131 and 16 days pass, how much I-131 do you have left?

alexandr1967 [171]

Answer:

Explanation:

2 half-lives will pass. Therefore the amount will be quartered into 2g.

3 0

3 years ago

What is the concentration of a solution with 2.00 moles of solute in 4.00 l of solution?

jarptica [38.1K]

Explanation:

Molarity is defined as the the number of moles present in a solution divided by volume in liters.

Mathematically, Molarity = $\frac{/text{no. of moles}}{volume in liter}$

As it is given that number of moles present into the solution are 2.00 moles and volume is 4 liter. Therefore, calculate the molarity of solution as follows.

Molarity = $\frac{/text{no. of moles}}{volume in liter}$

= $\frac{2.00 moles}{4.00 L}$

= 0.5 M

Thus, we can conclude that the concentration of given solution is 0.5 M.

6 0

3 years ago