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Subtract the following:
A) 18 rupees 9 paise from 75 rupees 80 paise.
B) 49 rupees 79 paise from 123 rupees 68 paise.
Answer
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Hint: Use decimal concept.
We know that, 1 rupee = 100 paise. We can reframe these questions as follows:
18 rupees 9 paise from 75 rupees 80 paise
18 rupees 9 paise can be represented as 18.09 rupees and 75 rupees 80 paise can be represented as 75.80 rupees. Now, on subtracting we’ll get,
75.80−18.09−−−−−− 57.71
Which means 57 rupees 71 paise
49 rupees 79 paise from 123 rupees 68 paise
49 rupees 79 paise can be represented as 49.79 rupees and 123 rupees 68 paise can be represented as 123.68 rupees. Now, on subtracting we’ll get,
123.68 −49.79−−−−−− 73.89
Which means 73 rupees 89 paise.
Note: We can also perform the subtraction by making all units the same that are paise and then subtract.
Answer:
I belive it is C
Step-by-step explanation:
It is between 3.1 and 3.17 or 3.2 if you want it by hundredths.
This is because 3.16 is 3.1600000 and many more zeros but 3.16227766 is slightly over that so it would be between 3.1 and 3.17.
Answer:
y = 7/5 x + 31
Step-by-step explanation:
To find the slope, we need to use the formula
m = (y2-y1)/(x2-x1)
m =(-4-17)/(5- -10)
= -21/(5+10)
= 21/15
Divide the top and bottom by 3.
= 7/5
The slope is 7/5.
Using the point slope form of the equation,
y-y1 = m(x-x1)
y-17 = 7/5 (x--10)
y-17 = 7/5(x+10)
Distribute the 7/5 ths.
y-17 = 7/5 x + 7/5*10
y-17 = 7/5 x +14
Add 17 to each side
y = 7/5 x + 14 + 17
y = 7/5 x + 31
This is in slope intercept form, with the slope being 7/5 and the y intercept of 31
Answer:
P = 2000 * (1.00325)^(t*4)
(With t in years)
Step-by-step explanation:
The formula that can be used to calculated a compounded interest is:
P = Po * (1 + r/n) ^ (t*n)
Where P is the final value after t years, Po is the inicial value (Po = 2000), r is the annual interest (r = 1.3% = 0.013) and n is a value adjusted with the compound rate (in this case, it is compounded quarterly, so n = 4)
Then, we can write the equation:
P = 2000 * (1 + 0.013/4)^(t*4)
P = 2000 * (1.00325)^(t*4)
