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Ray Of Light [21]
3 years ago
7

Im working on reflections and I am confused on what the reflection of A would be? I'm trying to find the reflection of (0,5) ove

r the Yaxis? The rule is this: (x,y)->(-x,y) but there is no such thing as -0......so... yea thats why im confused? Or is the reflection unchanging? is A'=0,5?

Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0
Any points that lie on the line of reflection (the mirroring line) will not move. So point A = (0,5) will become A' = (0,5) staying in the same location. Anything on the y axis will stay where it is.
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<u>Step-by-step explanation:</u>

y = ax² ; where a represents the vertical stretch

a reflection across the x-axis is represented by making the a-value negative.

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How can you solve an equation with a variable on ni tu sides?​
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Answer:

  Subtract from both sides of the equation the term you don't want

Step-by-step explanation:

In solving equations, you generally want to "undo" operations that are done to the variable. Addition is "undone" by adding the opposite (that is, subtracting the amount that was added). Multiplication is "undone" by division.

If you have variables on both sides of the equation, pick one of the variable terms and subtract it from both sides of the equation.

<u>Example</u>

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If we choose to subtract x, then we will have a variable term on the left and a  constant term on the right:

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Note that we purposely set up this example so that removing the variable term from the right side caused the variable term and constant term to be on opposite sides of the equal sign. It may not always be that way. As long as you remember that an unwanted term can be removed by subtracting it (from both sides of the equation), you can deal with constant terms and variable terms no matter where they appear.

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<em>Additional Comment</em>

It usually works well to choose the variable term with the smallest (or most negative) coefficient. That way, when you subtract it, you will be left with a variable term that has a positive coefficient.

3 0
3 years ago
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