Since a slope differe, this is not linear relationship. Simply, if you connect all points on the graph, they will not lie on the same line. Two next graphs represent the linear relationships, so they represent the linear relationship.
Answer:
8.85% per year
Step-by-step explanation:
To find the interest rate of a compounding interest, we use the formula:
![r=n[(\dfrac{A}{P})^{\dfrac{1}{nt}}-1]](https://tex.z-dn.net/?f=r%3Dn%5B%28%5Cdfrac%7BA%7D%7BP%7D%29%5E%7B%5Cdfrac%7B1%7D%7Bnt%7D%7D-1%5D)
Before we start solving, let's break down all the variables that we have.
A = 19,992.71
P = 10,000.00
n = 2
t = 8
r = ?
Now let's put the values into the formula.
![r=2[(\dfrac{19,992.71}{10,000.00})^{\dfrac{1}{2(8)}}-1]](https://tex.z-dn.net/?f=r%3D2%5B%28%5Cdfrac%7B19%2C992.71%7D%7B10%2C000.00%7D%29%5E%7B%5Cdfrac%7B1%7D%7B2%288%29%7D%7D-1%5D)
![r=2[(\dfrac{19,992.71}{10,000.00})^{\dfrac{1}{16}}-1]](https://tex.z-dn.net/?f=r%3D2%5B%28%5Cdfrac%7B19%2C992.71%7D%7B10%2C000.00%7D%29%5E%7B%5Cdfrac%7B1%7D%7B16%7D%7D-1%5D)
![r=2[(\dfrac{19,992.71}{10,000.00})^{0.0625}-1]](https://tex.z-dn.net/?f=r%3D2%5B%28%5Cdfrac%7B19%2C992.71%7D%7B10%2C000.00%7D%29%5E%7B0.0625%7D-1%5D)
![r=2[(1.9992.1)^{0.0625}-1]](https://tex.z-dn.net/?f=r%3D2%5B%281.9992.1%29%5E%7B0.0625%7D-1%5D)
![r=2[1.0442499885-1]](https://tex.z-dn.net/?f=r%3D2%5B1.0442499885-1%5D)
![r=2[0.0442499885]](https://tex.z-dn.net/?f=r%3D2%5B0.0442499885%5D)
or 
So the rate the Mrs. Emily Francis got from the bank was 8.85% per year.
14% of $15,500 is $2,170. $15,500 minus $2,170 is $13,330.
When the car is on sale, the price is reduced from $15,500 to $13,330.
3x^2 -6x + 6 :) hope this is alright