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3 years ago

Hello can you please help me posted picture of question

Mathematics

1 answer:

stellarik [79]3 years ago

8 0

Correct answer is option B

The solution is listed below:

$(-10 x^{3}+4x+5)+(5 x^{2} -2x) \\ \\ 
= -10 x^{3}+4x+5+5 x^{2} -2x \\ \\ 
=-10 x^{3}+5 x^{2} +2x+5$

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B-10 > 5; 14, 15, 16

torisob [31]

B = 16
explanation:
b-10 > 5
16-10 > 5
6 > 5
The other answer choices are less than or equal to 5

3 0

2 years ago

For a class trip, there are two adults for every 15 students. There are 238 people (adults and students) on the trip. How many s

-Dominant- [34]

Answer:

210

Step-by-step explanation:

x = num of adults

x + 7.5x = 238

8.5x = 238

x = 28

#students = 238-x

= 210

8 0

2 years ago

Unsure how to do this calculus, the book isn't explaining it well. Thanks

krok68 [10]

One way to capture the domain of integration is with the set

$D = \left\{(x,y) \mid 0 \le x \le 1 \text{ and } -x \le y \le 0\right\}$

Then we can write the double integral as the iterated integral

$\displaystyle \iint_D \cos(y+x) \, dA = \int_0^1 \int_{-x}^0 \cos(y+x) \, dy \, dx$

Compute the integral with respect to $y$ .

$\displaystyle \int_{-x}^0 \cos(y+x) \, dy = \sin(y+x)\bigg|_{y=-x}^{y=0} = \sin(0+x) - \sin(-x+x) = \sin(x)$

Compute the remaining integral.

$\displaystyle \int_0^1 \sin(x) \, dx = -\cos(x) \bigg|_{x=0}^{x=1} = -\cos(1) + \cos(0) = \boxed{1 - \cos(1)}$

We could also swap the order of integration variables by writing

$D = \left\{(x,y) \mid -1 \le y \le 0 \text{ and } -y \le x \le 1\right\}$

and

$\displaystyle \iint_D \cos(y+x) \, dA = \int_{-1}^0 \int_{-y}^1 \cos(y+x) \, dx\, dy$

and this would have led to the same result.

$\displaystyle \int_{-y}^1 \cos(y+x) \, dx = \sin(y+x)\bigg|_{x=-y}^{x=1} = \sin(y+1) - \sin(y-y) = \sin(y+1)$

$\displaystyle \int_{-1}^0 \sin(y+1) \, dy = -\cos(y+1)\bigg|_{y=-1}^{y=0} = -\cos(0+1) + \cos(-1+1) = 1 - \cos(1)$

7 0

1 year ago

Show the distributive property when solving 6 times 9 I need a answer

dsp73

Probably too late but 6*6+6*3

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120 grams half life at 45 days would be 60 then half life of 60 in another 45 days (90 total) should be 30 grams

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