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Sidana [21]
3 years ago
10

Hello can you please help me posted picture of question

Mathematics
1 answer:
stellarik [79]3 years ago
8 0
Correct answer is option B

The solution is listed below:

(-10 x^{3}+4x+5)+(5 x^{2} -2x) \\  \\ 
= -10 x^{3}+4x+5+5 x^{2} -2x \\  \\ 
=-10 x^{3}+5 x^{2} +2x+5
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Workout the probability that spinner A lands on 2 and spinner b does not land on b
zzz [600]

Spinner diagram isn't attached. A related spinner diagram has been attached below to provide an hypothetical solution to the problem

Answer:

4 / 15

Step-by-step explanation:

For the numbered spinner :

P(landing on 2) = required outcome / Total possible outcomes

Total possible outcomes = (1, 2, 3) = 3

Required outcome = (1) = 1

P(landing on 2) = 1 /3

Lettered spinner :

P(does not land on b)

Total possible outcomes = (A, B, C, D, E)

Required outcome = (a, c, d, e)

P(does not land on b) = 4 / 5

Hence,

P(lands on 2, does not land on b) in this scenario is :

1/3 * 4/5 = 4 / 15

5 0
3 years ago
Parallelogram (x 40) and (3x)
fenix001 [56]
<span>x-y=2y -> x=3y and 
3x-40+2y=180 --> 9y-40+2y=180 --> 11y=220 --> y=20, x=60 --> <A=<C=140 degrees, <B=<D=40 degrees.</span>
8 0
3 years ago
72.4 divided by 4 please help!!!!
wariber [46]

Answer:

18.1

hope it helps mate

8 0
3 years ago
Read 2 more answers
A manufactured lot of buggy whips has 20 items, of which 5 are defective. A random sample of 5 items is chosen to be inspected.
dimulka [17.4K]

Answer:

a. 39.55%

b. 44.02%

Step-by-step explanation:

We have the following data:

n = 5

x = 1

p = 5/20 = 0.25

to. If the sampling is done with replacement.

We apply the binomial distribution formula, which is as follows:

P = nCx * (p ^ x) * ((1-p) ^ (n-x))

Where nCx, is a combination, and is equal to:

nCx = n! / x! * (n-x)!

replacing we have:

5C1 = 5! / 1! * 4! = 5

replacing in the main formula:

P = 5 * (0.25 ^ 1) * ((1- 0.25) ^ (5-1))

P = 0.3955

that is, without replacing the probability is 39.55%

b. if the sampling is done without replacement.

Here it is a little different from the previous one, but what you should do is calculate three cases,

the first was the one at point a, when n = 5 and x = 1

5C1 = 5! / 1! * 4! = 5

the second is when n = 20 and x = 5, this is all possible scenarios.

20C5 = 20! / 5! * 15! = 15504

and the third is when n = 15 (20-5) and x = 4 (5-1), which corresponds to the cases when none were damaged

15C4 = 15! / 4! * 11! = 1365

In the end, it would be:

P = (5C1 * 15C4) / 20C5

Replacing:

P = 5 * 1365/15504

P = 0.4402

Which means that without replacing the probability is 44.02%

7 0
3 years ago
A television costs $450. During a special sale, it’s marked 1\3 off. What’s the sales price of the tv?
Darina [25.2K]

Answer:

150

Step-by-step explanation:

4 0
4 years ago
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