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Drupady [299]
3 years ago
9

What percent of 25 is 20

Mathematics
2 answers:
ipn [44]3 years ago
7 0
80% bc 20/25 equals 4/5 and 4/5 equals x/100 and when you do that math it equals 80%
oksian1 [2.3K]3 years ago
6 0

What percent of 25 equals 20

If x is the percentage,

25 * x = 20

We would multiply x by 25 because when the question includes "of" it indicates multiplication

Divide both sides of the equation by 25 to isolate x, what we want to find out

x = 0.8

The percent (x) is in decimal form, to convert it to a percent move the decimal 2 spaces down- basically multiply it by 100

x = 80%

20 is 80% of 25


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Nine tiles are numbered $\color[rgb]{0.35,0.35,0.35}1, 2, 3, \ldots, 9$. Each of three players randomly selects and keeps three
Eduardwww [97]

The probability that all three players obtain an odd sum is 3/14.

<h3>What is probability?</h3>

The probability is the ratio of possible distributions to the total distributions.

I.e.,

Probability = (possible distributions)/(total distributions)

<h3>Calculation:</h3>

Given that,

There are nine tiles - 1, 2, 3,...9, respectively.

A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.

In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.

The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.

So,

One player can be selected in ^3C_1  ways.

The 3 odd tiles out of 5 can be selected in ^5C_3 ways.

The remaining 2 odd tiles can be selected and distributed in ^2C_1 ways.

The remaining 4 even tiles can be equally distributed in \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !} ways.

So, the possible distributions = ^3C_1 × ^5C_3 × ^2C_1 × \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !}

⇒ 3 × 10 × 2 × 6 = 360

To find the total distributions,

The first player needs 3 tiles from the 9 tiles in ^9C3=84 ways

The second player needs 3 tiles from the remaining 6 tiles in ^6C_3=20 ways

The third player takes the remaining tiles in 1 way.

So, the total distributions = 84 × 20 × 1 = 1680

Therefore, the required probability = (possible distributions)/(total distributions)

⇒ Probability = 360/1680 = 3/14.

So, the required probability for the three players to obtain an odd sum is 3/14.

Learn more about the probability of distributions here:

brainly.com/question/2500166

#SPJ4

3 0
2 years ago
A roll of ribbon was 12 meters long. Diego cut 9 pieces of ribbon that were 0.4 meters each to tie some presents. He then used t
Alex777 [14]

Answer:

8.4 meters of ribbon left and 14 wreaths made

Step-by-step explanation:

9 * 0.4 = 3.6 meters used for presents

12 - 3.6 = 8.4 meters left for wreaths

8.4 / 0.6 = 14 wreaths

4 0
3 years ago
Read 2 more answers
Use the following frequency distribution (of SAMPLE DATA) in answering the questions: class 0-9 f=10; class 10-19 f=20; class 20
lutik1710 [3]

Answer:

1. Five classes in the frequency distribution

2.The mid point of the third class is 24.5

3.The total number of frequency is 100

4.The relative frequency of the third class is (20/100=0.2)

5. We use n-1 because we are dealing with a sample data

6. The mean is 24.5

7. The value of the standard deviation is 11

Step-by-step explanation:

See attached picture for the solutions

4 0
3 years ago
Find x <br> Picture Below
Mumz [18]

m∠BEC=(1/2)(mBC + mAD)

110 = (1/2)(x+97)

220 = x+97

x=220 - 97

x= 123⁰

7 0
3 years ago
How would I solve; A bakery has 456 dozen cookies. How many individual cookies are there ?
Over [174]

Hi :")

Answer:

5472

Step-by-step explanation:

a dozen = 12 identical bodies

456 dozen cookies there are

12 x 456 = 5472

Good Luck ;)

#Turkey

6 0
3 years ago
Read 2 more answers
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