Answer:
C
Explanation:
An educated guess and also i think because it has the word muscle in it
Answer:
R = 710.7N
L = 67.689 N
During gravity fall L = R = 0 N
Explanation:
So the acceleration that the elevator is acting on the woman (and the package) in order to result in a net acceleration of 0.15g is
g + 0.15g = 1.15g
The force R that the elevator exerts on her feet would be product of acceleration and total mass (Newton's 2nd law):
a(m + M) = 1.15g(57 + 6) = 1.15*9.81*63 = 710.7N
The force L that she exerts on the package would be:
am = 1.15g *6 = 1.15*9.81*6 = 67.689N
When the system is falling, all have a net acceleration of g. So the acceleration that the elevator exerts on the woman (and the package) is 0, and so are the forces L and R.
Answer:
a. effort
Explanation:
im really sorry really really sorry if this is wrong i am truley really sorry i am so sorry if this is wrong im not 100% sure this is the right answer
<span>This projectile has been thrown in an oblique movement, so it’s moving in x and in y at the same time. Vy varies due to gravity, and Vx is a constant as there is no gravity in the horizontal direction. In order to calculate Vx, you have to use the angle:
Vx=V*cosa=12m/s*cos(14.2)= 11.6m/s
So now you should use Vx the same way it is used in a uniform linear movement.
d=v*t
dx=vx*t
t=dx/vx=7m/(11.6m/s)=0.603s</span>
This question is incomplete. The complete question is given below:
Question 3 Both the angle and the magnitude of the force have a certain uncertainty: εF = 28 N and εθ = 0.8°. Using the propagation methods described in the video you watched at the beginning of this prelab, calculate the corresponding propagated uncertainty for Fx, in N. For this question, round up your final answer to two significant figures. Do not include the ± sign in your answer. Example: If the x component of F is 200±14 N, you should enter “14”.
Both the force and the angle are measured, and the results are quoted as a central value plus/minus an uncertainty:
F = F0 ± εF
θ = θ0 ± εθ
We would like to evaluate the component of the force in the x direction.
Question 2
Let us first concentrate on the central value. Take F0 = 325 N and θ0 = 57°.
The answer & explanation for this question is given in the attachment below.