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3 years ago

PLEASE HELP!!!! Define constructive interference.

1 answer:

8 0

Constructive interference is a phenomenon in optics where the crest or troughs of two or more waves intersect each other. This leads to increase in the intensity of the output wave.

Explanation:

When two or more waves emitting from different sources travel together, they tend to intersect at some point. So the waves can intersect either at both the crusts position and both the waves in trough position. Thus if the intersecting points of the superposing waves are same, then it will lead to constructive interference leading to formation of bright light.

But if the intersecting points of the superposing waves are different, for example the crust of one wave is intersecting with trough of other wave, then it will lead to destructive interference. The output of the destructive interference is a dark spot in those regions.

Thus, constructive interference increases the amplitude of the superimposing waves as they add up the intensities of crusts of all intersecting points or troughs of all intersecting points.

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A net force of 60 N north acts on an object with a mass of 30 kg. Use Newton's second law of

earnstyle [38]

Answer:

Explanation:

F = ma. For us, this looks like

60 = 30a and

a = 2 m/s/s

If the force goes up to, say, 90, then

90 = 30a and

a = 3...if the force goes up, the acceleration also goes up.

If the mass goes up to say, 60, and the force stays the same, then

60 = 60a and

a = 1...if the mass goes up, the acceleration goes down.

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3 years ago

*please refer to photo* An electric field of magnitude 5.25 ✕ 10^5N/C points due south at a certain location. Find the magnitude

kvv77 [185]

Answer:

Approximately $3.86\; {\rm N}$ (given that the magnitude of this charge is $-7.35\; {\rm \mu C}$ .)

Explanation:

If a charge of magnitude $q$ is placed in an electric field of magnitude $E$ , the magnitude of the electrostatic force on that charge would be $F = E\, q$ .

The magnitude of this charge is $q = 7.35\; {\rm \mu C}$ . Apply the unit conversion $1\; {\rm \mu C} = 10^{-6}\; {\rm C}$ :

$\begin{aligned} q &= 7.35\; {\mu C} \times \frac{10^{-6}\; {\rm C}}{1\; {\mu C}} = 7.35\times 10^{-6}\; {\rm C}\end{aligned}$ .

An electric field of magnitude $E = 5.25\times 10^{5}\; {\rm N \cdot C^{-1}}$ would exert on this charge a force with a magnitude of:

$\begin{aligned}F &= E\, q \\ &= 5.25 \times 10^{5}\; {\rm N \cdot C^{-1}} \times (-7.35\times 10^{-6}\; {\rm C}) \\ &\approx 3.86\; {\rm N}\end{aligned}$ .

Note that the electric charge in this question is negative. Hence, electrostatic force on this charge would be opposite in direction to the the electric field. Since the electric field points due south, the electrostatic force on this charge would point due north.

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2 years ago

What type of tide occurs when the sun, moon, and earth form a right triangle in space?

stiks02 [169]

Neap tide is your answer

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3 years ago

Compared to water, most metals have low specific heats. true or false

Alchen [17]

Yes that's a true statement. That's why grandmother put a hot water bottle to warm up her bed, and not a hot bar of steel or lead.

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4 years ago