PLEASE HELP!!!! Define constructive interference.

1 answer:

8 0

Constructive interference is a phenomenon in optics where the crest or troughs of two or more waves intersect each other. This leads to increase in the intensity of the output wave.

<u>Explanation:</u>

When two or more waves emitting from different sources travel together, they tend to intersect at some point. So the waves can intersect either at both the crusts position and both the waves in trough position. Thus if the intersecting points of the superposing waves are same, then it will lead to constructive interference leading to formation of bright light.

But if the intersecting points of the superposing waves are different, for example the crust of one wave is intersecting with trough of other wave, then it will lead to destructive interference. The output of the destructive interference is a dark spot in those regions.

Thus, constructive interference increases the amplitude of the superimposing waves as they add up the intensities of crusts of all intersecting points or troughs of all intersecting points.

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A pendulum consisting of a 0.5 kg mass tied to a 0.3 m string is set into oscillation at the same moment that a stone is dropped

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Answer:

2.72 cycles

Explanation:

First of all, let's find the time that the stone takes to reaches the ground. The stone moves by uniform accelerated motion with constant acceleration g=9.8 m/s^2, and it covers a distance of S=44.1 m, so the time taken is

$S=\frac{1}{2}at^2\\t=\sqrt{\frac{2S}{a}}=\sqrt{\frac{2(44.1m)}{9.8 m/s^2}}=3 s$

The period of the pendulum instead is given by:

$T=2 \pi \sqrt{\frac{L}{g}}=2 \pi \sqrt{\frac{0.3 m}{9.8 m/s^2}}=1.10 s$

Therefore, the number of oscillations that the pendulum goes through before the stone hits the ground is given by the time the stone takes to hit the ground divided by the period of the pendulum:

$N=\frac{t}{T}=\frac{3 s}{1.10 s}=2.72$