Answer:
The correct answer to the following question will be option c. Store Code.
Explanation:
A store code will be the unique ID which can uniquely identify any location of that store.
- Any random number or name can be the store code.
- A store code in each Google My Business (GMB) will only be viewable to the person who is managing that locations arround the store.
- Any costumer doesn't have possibility to see it.
Hence, Option C is the right answer.
Answer:
A compiler takes the program code (source code) and converts the source code to a machine language module (called an object file). Another specialized program, called a linker, combines this object file with other previously compiled object files (in particular run-time modules) to create an executable file. In short, it's A or D.
<span>Data consolidation is the gathering and/or integration of data coming from many and diverse sources and going into a single destination. Meanwhile this process is taking place, different data sources are consolidated, into a single data store.
Hope this helps.</span>
Answer:
int k;
double d;
char s[10];
cin >> k >> d >> s;
cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s;
Explanation
First Step (declare K, d, s) so they can store a integer
int k;
double d;
char s[10];
Second Step (read in an integer, a real number and a small word)
cin >> k >> d >> s;
Third Step ( print them out )
cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s;
Answer:
Option a. int max = aList.get(0); for (int count = 1; count < aList.size(); count++) { if (aList.get(count) > max) { max = aList.get(count); } }
is the correct code snippet.
Explanation:
Following is given the explanation for the code snippet to find largest value in an integer array list aList.
- From the array list aList, very first element having index 0 will be stored in the variable max (having data type int).
- By using for starting from count =1 to count = size of array (aList), we will compare each element of the array with first element of the array.
- If any of the checked element get greater from the first element, it gets replaced in the variable max and the count is increased by 1 so that the next element may be checked.
- When the loop will end, the variable max will have the greatest value from the array aList.
i hope it will help you!
