Your goal is to have x by itself
Send st to other side
rx= r+st
Divide by r so x stays alone
X=(r+st)/r
Which is also equal to
X=r/r+st/r
X= 1+st/r
Answer:
Step-by-step explanation:
You can start by recognizing 19/12π = π +7/12π, so the desired sine is ...
sin(19/12π) = -sin(7/12π) = -(sin(3/12π +4/12π)) = -sin(π/4 +π/3)
-sin(π/4 +π/3) = -sin(π/4)cos(π/3) -cos(π/4)sin(π/3)
Of course, you know that ...
sin(π/4) = cos(π/4) = (√2)/2
cos(π/3) = 1/2
sin(π/3) = (√3)/2
So, the desired value is ...
sin(19π/12) = -(√2)/2×1/2 -(√2)/2×(√3/2) = -(√2)/4×(1 +√3)
Comparing this form to the desired answer form, we see ...
A = 2
B = 3
In order to solve this we need to get x by itself on one side.
We need o start by adding across the 4 so that we get:
x/3 = -7 + 4 = -3
We then need to multiply both sides by 3 to get a singular x:
x = -3 * 3 = -9
Answer:
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