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4 years ago

6

We place a small pressure sensor at a certain depth in water. with which orientation does the sensor register the greatest press

ure, or is the reading the same in all directions?

1 answer:

Dominik [7]4 years ago

7 0

Hydrostatic pressure is independent of directions.

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An astronaut weighs 8.00x10^2 newtons on the surface of Earth. What is the weight of the astronaut 6.37x10^6 meters above the su

Orlov [11]

800/2^2=2.oo10^10^2N

8 0

4 years ago

Can a body have mass but no weight give reasion for your answer

EleoNora [17]

Answer:

Hey buddy, here is your answer. Hope it helps you.

Explanation:

Yes, weight of a body is not constant, it varies with the value of acceleration due to gravity, g. Weight of a body is zero, when it is taken to the centre of the earth or in the interplanetary space, where g=0. Mass is the total matter in a body, while weight is the force by which the body is attracted.

Weight is never constant while mass is. So we can have weight zero but with some mass. This will happen when an object is at the centre of earth, as g=0 at centre of earth , so weight will be 0 while mass will always be constant everywhere

5 0

3 years ago

Read 2 more answers

A car tire rotates at a constant angular velocity of 3.5 rotations during a time interval of 0.75 seconds. What is the angular s

Andru [333]

Answer : $\theta = 2.625\ radians$

Explanation :

Given that,

Angular velocity $\omega = 3.5\ rad/s$

Time $t = 0.75 s$

We know , the formula of angular velocity

$\omega = \dfrac{\theta}{t}$

$\theta = \omega \times t$

$\theta = 3.5\ rad/s\times0.75\ s$

The angular speed of the tire is

$\theta = 2.625\ radians$

Hence, this is the required solution.

4 0

3 years ago

Which of these processes describes the effect Earth's atmosphere has on Earth's hydrosphere?

Ede4ka [16]

Warm, moist air increasing ocean temp

6 0

4 years ago

Two objects, one 4 times as massive as the other, are approaching each other under their mutual gravitational

marusya05 [52]

To Find :

The acceleration of the heavier object.

Solution :

Force of gravitation on lighter object by heavier object is :

$F = \dfrac{Gm(4m)}{100^2}$

Acceleration of lighter object is given by :

$a_s = \dfrac{4Gm}{100^2}\\\\m = \dfrac{50^2}{G}$ .....1)

Now, acceleration of heavier object when separation between them is 25 km :

$4ma_h = \dfrac{Gm(4m)}{25}\\\\a_h = \dfrac{Gm}{25}$ .....2)

Putting value of m in equation 2, we get :

$a_h = \dfrac{G\times 50^2}{G \times 25}\\\\a_h = \dfrac{2500}{25}\\\\a_h = 100\ m/s^2$

Therefore, the acceleration of the heavier object is 100 m/s².

6 0

3 years ago