Answer:
i)4080000V
ii)4080000V
iii)5766400v
Explanation:
Hello!
To solve this problem we will use the following steps
1. We will use the equation that defines the distance between two points in order to find the distance from the origin to each of the points that the problem asks for.
x= horizonalt component
y=vertical component
d=distance
i)
x=0
y=6
ii)
x=6
y=0
iii).
x=6
y=6
2.we calculate the voltage at each point using the equation that relates the distance the voltage and the electric field
V=Ed
where
V=EPD= the electric potential difference
E=electric field magnitude=6.8 × 10^5 N/C.
d=distance
i)
V=Ed=(6.8 × 105 N/C.)(6)=4080000V
ii)
i)
V=Ed=(6.8 × 105 N/C.)(6)=4080000V
iii)
i)
V=Ed=(6.8 × 105 N/C.)(8.48m)=5766400v
Pressure Law: constant volume
Convert all Temperatures to Kelvin
0°C= 273K
answer= 312Kelvin
(16.8 kW) means (16,800 joules/second)
Energy in 1 hour = (1 hour) x (16,800 J/s) x (3,600 s/hour)
Energy = (16,800 x 3,600) J
Energy = 60,480,000 Joules
Energy = 60.48 MJ
Answer:
When one system vibrating at its natural frequency is put closer to a stationary system, the stationary system receives impulses.
At resonant frequency, the system vibrating at its own natural frequency suddenly goes on decreasing in order to cope with neighboring system.
These decrease in frequency is known as damping.
Answer:
Por lo tanto, la presión del ozono es:
Explanation:
Podemos usar la ecuacion de los gases ideales;
(1)
Tenemos:
El volumen V = 224 dm³ = 224 L
La temperatura T = 51.09 C = 324.09 K
La masa es m = 4.561 kg
Lo necesitamos ahora es calvular n que es el numero de moles;
recordemos que el peso molecular del ozono M = 48 g/mol.
Finalmente, usando la ecuacion 1 despejamos la presion P
Por lo tanto, la presion del ozono es:
Espero te haya ayudado!
