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DochEvi [55]
3 years ago
9

In your own words, explain the effects of changes in Earth's magnetic field over time.

Physics
2 answers:
Snezhnost [94]3 years ago
8 0

Answer:

Earth magnetic field may exist due to many causes out of which the most dominating cause is the molten metal inside the core of Earth which will contain large number of ions.

All ions will revolve along with the Earth due to which there exist a current loop due to motion of ions. Now this current may induce magnetic field due to Earth.

Now here the magnetic field of Earth is inclined at some angle with the axis of rotation of Earth. and the North pole of magnet is near the geographic South pole of Earth.

So here by observation it is found that the angle between the magnetic field axis and axis of rotation of Earth is changing with time. This angle is increasing in magnitude.

So there is just change in orientation observed so far due to magnetic field of Earth.

viva [34]3 years ago
3 0
It's an interesting fact that scientists don't fully understand how it works. But it seems to be to do with molten metal circulating in the core. Given that it's just liquid metal sloshing around, it seems understandable that it won't always circulate perfectly - imagine the cloud bands in Jupiter's atmosphere - they are reasonably stable but change from time to time. When the liquid changes its speed or direction, however slowly it does so, the resulting magnetic field will move or switch direction.

<span> As scientists try to build better mathematical models of how the core works, they should be able to learn more about the magnetic field it produces. Hope this helps</span>
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A cylindrical tube sustains standing waves at the following frequencies: 600 Hz, 800 Hz, and 1000 Hz. The tube does not sustain
Thepotemich [5.8K]

Answer:

Explanation:

In  closed organ pipe notes with odd harmonics are produced and in open organ pipe notes with all odd and even harmonics are produced. notes with frequencies 600, 800 and 1000 Hz are produced. These are 3 , 4 and 5 times 200 Hz. ie both odd and even times of 200 . So fundamental frequency appears to be 200 Hz. There is no note available between 800 and 1000. It also indicates that 200 Hz is the fundamental frequency and the pipe is open at both ends.

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3 years ago
Which of the following is not true about minerals?
mezya [45]

Answer:

I think it's A but I'm not sure

6 0
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1) What would the average acceleration be for a car at a stoplight that speeds up to 20 m/s in 10 seconds (in m/s^2)
Alexxx [7]
1.)
Velocity is in m/s, and acceleration is in m/s^2 like you said. Because of this, we can calculate this by dividing the speed by the time it took to get to that speed.
(20 meters/second) / 10 seconds = 2 meters/ second^2

2.)
Same thing with the first one.
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Which atom in a water molecule has the greatest electronegativity??
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g In 1956, Frank Lloyd Wright proposed the construction of a mile-high building in Chicago. Suppose the building had been constr
Lorico [155]

To solve this problem it is necessary to apply the concepts related to acceleration due to gravity, as well as Newton's second law that describes the weight based on its mass and the acceleration of the celestial body on which it depends.

In other words the acceleration can be described as

a = \frac{GM}{r^2}

Where

G = Gravitational Universal Constant

M = Mass of Earth

r = Radius of Earth

This equation can be differentiated with respect to the radius of change, that is

\frac{da}{dr} = -2\frac{GM}{r^3}

da = -2\frac{GM}{r^3}dr

At the same time since Newton's second law we know that:

F_w = ma

Where,

m = mass

a =Acceleration

From the previous value given for acceleration we have to

F_W = m (\frac{GM}{r^2} ) = 600N

Finally to find the change in weight it is necessary to differentiate the Force with respect to the acceleration, then:

dF_W = mda

dF_W = m(-2\frac{GM}{r^3}dr)

dF_W = -2(m\frac{GM}{r^2})(\frac{dr}{r})

dF_W = -2F_W(\frac{dr}{r})

But we know that the total weight (F_W) is equivalent to 600N, and that the change during each mile in kilometers is 1.6km or 1600m therefore:

dF_W = -2(600)(\frac{1.6*10^3}{6.37*10^6})

dF_W = -0.3N

Therefore there is a weight loss of 0.3N every kilometer.

4 0
4 years ago
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