The ball's maximum height is 30.25 feet.
<h3>What is quadratic equation?</h3>
A quadratic equation in math is a second-degree equation of the form ax² + bx + c = 0. Here a, b, are the coefficients, c is the constant term, and x is the variable.
Given:
h= -16t²+36t+10
Differentiate w.r.t. 't',
h' = -32t+36
When h=0, that will be the maximum height
32t= 36
t= 9/8
t= 1.125 sec.
So, The maximum height is
h(1.123)= -16(1.125)² + 36*1.125+10
h(1.125) = 30.25 feet.
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Answer:
x=1
Step-by-step explanation:
Substitute the value of y to the first given
3x+4(-x)=-1
3x+(-4x)=-1
-x=-1
divide both sides by -1
x=1
Answer:
14
Step-by-step explanation:
A triangle with 45 degrees on one corner and 90 degrees on another has 45 degrees on the third corner (180-side1-side2=side3). Therefore that’s an isosceles triangle, which has the same length on the two sides next to the right angle. To get the length of the third side, remember that for any right triangle, the longest side is equal to the square root of :(the first side squared)+(the second side squared). A^2+b^2=c^2 or c=sqrt(a^2+b^2). If you do the math, sqrt((7sqrt2)^2+(7sqrt2)^2)=14. That’s your third side length, x=14.
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