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Find Radius :
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Radius of the semicircle = 10 ÷ 2 = 5cm
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Find Area of the semi circle :
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Area of the semi circle = 1/2 πr²
Area of the semi circle = 1/2 x π x (5)²
Area of the semi circle = 12.5π cm²
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Find Radius :
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Radius of the inner circle = 5 ÷ 2 = 2.5 cm
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Find area of inner circle :
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Area of the inner circle = πr²
Area of the inner circle = π x (2.5)²
Area of the inner circle = 6.25π
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Area of the shaded region :
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Area of the shaded region = 12.5π - 6.25π
Area of the shaded region = 6.25π
Area of the shaded region = 19.63 cm²
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Answer: Area of the shaded region = 19.63 cm²
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Let x - hours Carlos drove ; Let y - hours Maria drove
Equation 1: x + y = 4.4
x = 4.4 - y
Equation 2: 55x + 50y = 233
55(4.4 - y) + 50y = 233
242 - 55y + 50y = 233
-5y = 233-242
-5y = -9
y=9/5 or 1.8 hours Maria drove
To find time Carlos drove:
x=4.4 - 1.8
x = 2.6 hours
Answer:
Step-by-step explanation:
Type of equations,
Linear equations:
Equations in the form of y = mx + b
Quadratic equations:
Equation with a maximum degree = 2
y = ax² + bx + c
Exponential equations:
Any function or equation having exponent,
y = a(b)ˣ
a). f(x) = 3x + 2
Linear function.
b). y = 5ˣ
Exponential equation.
c). f(x) = 2
Linear equation
d). f(x) = 4(2)ˣ + 1
Exponential function
e). 
Exponential function
f). y = 4x² + 2x - 1
Quadratic function
Answer:
Step-by-step explanation:
If N is the midpoint of CD, it means that N bisects the line CD. Hence;
CN + ND = CD .... 1 and;
CN = ND .... 2
Substitute equation 2 into 1;
CN + CN = CD
2CN = CD
Rearrange;
CD = 2CN (proved)
The hypothesis is the midpoint hypothesis and the hypothesis is TRUE
