What is the equation in point−slope form of the line passing through (−2, −5) and (2, 3)?

1 answer:

8 0

Hi,

m = (y-y₀)/(x-x₀)
m = (-5-3)/(-2-2)
m = -8/-4
m = 2

For point (2,3) ⇒ x₀ = 2 and y₀ = 3

y-y₀ = m(x-x₀)
y-3 = 2(x-2)

For point (-2,-5) ⇒ x = -2 and y = -5

-5-3 = 2(-2-2)
-8 = 2(-4)
-8 = -8 ⇒ True

Answer:

C. The equation is y-3 = 2(x-2)

You might be interested in

A. What fraction of the students chose Website A? Write your answer in simplest form.

exis [7]

Answer:

no se hablar taka taka XD

5 0

2 years ago

Read 2 more answers

The simplified expression

Romashka-Z-Leto [24]

Answer:

$5x^2 y^2$

Step-by-step explanation:

We need to use the properties shown below to solve this:

1. $\sqrt[n]{x^a} =x^{\frac{a}{n}}$

2. $\sqrt{x}\sqrt{x} =x$

3. $\sqrt{x} \sqrt{y}=\sqrt{x*y}$

Area of a triangle is given by 1/2 * base * height, so we do that and simplify:

$A=\frac{1}{2}(\sqrt{5x^3} )(2\sqrt{5xy^4} )\\A=\frac{1}{2}(5x^3)^{\frac{1}{2}}*2*(5xy^4)^{\frac{1}{2}}\\A=\sqrt{5}x^{\frac{3}{2}}*\sqrt{5}\sqrt{x} } y^2\\A=\sqrt{5} \sqrt{5}x^{\frac{3}{2}} x^{\frac{1}{2}}y^2\\A=5*x^2y^2\\A=5x^2 y^2$