2 years ago

What is the equation in point−slope form of the line passing through (−2, −5) and (2, 3)?

1 answer:

8 0

Hi,

m = (y-y₀)/(x-x₀)
m = (-5-3)/(-2-2)
m = -8/-4
m = 2

For point (2,3) ⇒ x₀ = 2 and y₀ = 3

y-y₀ = m(x-x₀)
y-3 = 2(x-2)

For point (-2,-5) ⇒ x = -2 and y = -5

-5-3 = 2(-2-2)
-8 = 2(-4)
-8 = -8 ⇒ True

Answer:

C. The equation is y-3 = 2(x-2)

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Linear Equation, Need Solved Asap <3

s2008m [1.1K]

Step-by-step explanation:

y = 5x - 4

When x = 0, y = 5(0) - 4 = -4.

When x = 1, y = 5(1) - 4 = 1.

When x = 2, y = 5(2) - 4 = 6.

The 3 ordered pairs we have are (0,-4), (1,1) and (2,6).

We now check the point (-5,-29):

(-29) : 5(-5) - 4

-29 : -25 - 4

-29 : -29 => -29 = -29.

Since Left hand side = Right hand side, the point (-5,-29) is a solution.

5 0

2 years ago

Read 2 more answers

If f(x) = 8x2 + 4x - 12. Find f(2)<br> f(2)=

posledela

Answer:

f(2) = 28

Step-by-step explanation:

$\rm f(x) = 8 {x}^{2} + 4x - 12$

$\rm Evaluate \: 8 x^2 + 4 x - 12 \: where \: x = 2: \\ \\ \rm \implies f(2) = 8 \times {2}^{2} + 4 \times 2 - 12 \\ \\ \rm \implies f(2) = 8 \times 4 + 8 - 12 \\ \\ \rm \implies f(2) = 32 - 4 \\ \\ \rm \implies f(2) = 28$