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MrRissso [65]
3 years ago
14

I need help answering

Mathematics
1 answer:
Lady_Fox [76]3 years ago
8 0
Not sure I’ll be back with the anwer I need to get my calculator
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Bob wants to create two pens, as shown in the figure. One pen is for a garden and it needs a heavy duty fence to keep out the cr
sattari [20]
\bf \textit{the area of either pen is 2744, thus}\\\\
A=xy\implies 2744=xy\implies \cfrac{2744}{x}=y

\bf \begin{array}{llll}
\textit{perimeter of the garden pen}\\\\
P=2(x+y)\\\\
P=2\left( x+ \cfrac{2744}{x}\right)\\\\
P=2x+\cfrac{5488}{x}\\
----------\\

\textit{cost of it}\\\\
C=15\left( 2x+\cfrac{5488}{x} \right)\\\\
C=30x+\cfrac{82320}{x}
\end{array}\qquad 
\begin{array}{llll}
\textit{perimeter of the dog pen}\\\\
P=2x+y\\\\
P=2x+\cfrac{2744}{x}\\
----------\\
\textit{cost of it}\\\\
C=5\left( 2x+\cfrac{2744}{x} \right)\\\\
C=10x+\cfrac{27440}{x}
\end{array}

notice... the dog's pen perimeter, does not include the side that's bordering the garden's, since that side will use the heavy duty fence, instead of the light one

so, the sum of both of those costs, will be the C(x)

\bf C(x)=\left( 30x+\cfrac{82320}{x} \right)+\left( 10x+\cfrac{27440}{x} \right)
\\\\\\
C(x)=40x+\cfrac{109760}{x}

so, just take the derivative of it, and set it to 0 to find the extremas, and do a first-derivative test for any minimum

8 0
3 years ago
Are 5(2x-y) and 15x-5y equivalent expressions?
krek1111 [17]

No, they are not equivalent.

5(2x - y) = 10x - 5y and it is not equal to 15x - 5y.

(using distribution property)

6 0
3 years ago
A new teen magazine has a readership goal of 3.5 million. It's current readership is 2.8 million. How much does its readership n
Kazeer [188]

3,500,000 - 2,800,000 = 700,000

So the magazine needs 700,000 readers to meet their goal.

Hope that helps you. :-)

6 0
3 years ago
Read 2 more answers
PLEASE HELP IM BEING TIMED!!! WILL MARK BRAINLIEST FOR CORRECT ANSWER!!! 100PTS!!!
amid [387]

Answer:

B and D.

Step-by-step explanation:

We know that when we added the two functions together, we get:

h(x)=-x+9

However, when we multiplied them together, we get:

j(x)=-9x

Let's first consider what we can determine from this.

If we add them together, we get a linear equation. However, this doesn't mean that our two original functions are linear since if we have, say, -x^2 and x^2-x+9, they will cancel and form a linear equation if we add them together.

<em>However</em>, since we know that if we multiply the two functions together, we get a linear equation, this means that both our original functions must be linear.

<em>But</em>, if we multiplied two linear functions, then we should get a quadratic, since x times x will yield x².

Therefore, this means that one of our linear functions is a horizontal line with no x variable. This is the only way to have a linear equation when multiplied.

Therefore, we have determined that both of our original functions are linear functions, and one (only one of them) is a horizontal line.

Let's go through each of the answer choices.

A) Both functions must be quadratic.

This is false as we determined earlier. If this was true, then the resulting function should be a quartic and not a line. A is false.

B) Both functions must have a constant rate of change.

Remember that all linear equations have a constant rate of change.

Since we determined that both our original functions are linear equation, this means that both our functions will have a constant rate of change.

So, B is true.

C) Both functions must have a y-intercept of 0.

Remember that one of our functions is a horizontal line.

If the y-intercept was 0, then the equation of our horizontal line will be:

y=0

And we know that anything multiplied by 0 will give us 0. However, the product of our function is -9x.

So, C cannot be true.

Rather, only our linear equation (not the horizontal line) may have a y-intercept of 0.

D) The rate of change of either f(x) or g(x) must be 0.

Remember that we determined that one of our lines must a horizontal.

Remember that horizontal lines have a slope of 0. In other words, the rate of change is 0.

So, D is true.

E) The y-intercepts of f(x) and g(x) must be opposites.

Well, since B and D is are true, this must be false since we can only select two options ;D

But, we can think about this. Note that if we multiply the two functions, we have a function <em>without</em> a y-intercept.

Remember that our horizontal line is <em>not</em> 0. So, the y-intercept of the horizontal line is a number.

So, the opposite of a number is another number.

So, if we multiply two non-zero numbers, we <em>must</em> get another number.

However, from our product, j(x)=-9x, we don't have another number. The y-intercept from this is 0.

Therefore, the two y-intercepts <em>cannot</em> be opposites of each other. If it was so, then we should have a y-intercept. So, E must be false.

In fact, this means that the y-intercept of our line (not the horizontal one) <em>must </em>be 0.

So, our answers are B and D.

And we're done!

Edit: Some (minor) errors in reasoning. Sorry!

4 0
3 years ago
Read 2 more answers
What I Can Do
tankabanditka [31]

Answer:

10

5Stetpplanation:

8 0
3 years ago
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