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sesenic [268]
3 years ago
9

Evaluate if c=3 and d=-4 2c/d

Mathematics
1 answer:
lapo4ka [179]3 years ago
6 0
Substitute 3 into the expression for c and -4 for d. So, 2c/d = 2(3)/(-4) = 6/-4 = -3/2.  The answer is -3/2.
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Find the ratio of 4 meter to 50 centimetre
ladessa [460]

                          (4 meters)  /  (50 centimeters)

                  =      (4 x 100 centimeters)  /  (50 centimeters)

                  =      (400 centimeters)  /  (50 centimeters)

                  =              (400) / (50)

                  =                     8       .
4 0
3 years ago
Solve using method of your choice. PLease help 28 points
Burka [1]
7x+y=-20\\
x-3y=-50\\\\
21x+3y=-60\\
\underline{x-3y=-50}\\
22x=-110\\
x=-5\\\\
-5-3y=-50\\
3y=45\\
y=15


-----------------------------------------------------

(5x-8y)^2=-25
No solution in real numbers.
5 0
3 years ago
I need help fast!!!
Andre45 [30]
The first one is 4 x 10^-9
second one is 4 x 10^10
third one is 5 x 10^7
fourth on is 2 x 10^-5
8 0
3 years ago
Multiply<br><br> 2.5<br> 5.4 =<br><br> ​(Type an integer or a simplified​ fraction.)
zepelin [54]

Answer:

Fractional form of 2.5 is 5/2.

5.4 as a fraction is 27/5.

4 0
3 years ago
For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at
GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}

Now, let's add the components of the same direction:

\begin{gathered} V_x=W_x+A_x=35.35+0=35.35\\ \\ V_y=W_y+A_y=35.35-540=-504.65 \end{gathered}

To find the resultant bearing (theta), we can use the formula below:

\begin{gathered} \theta=\tan^{-1}(\frac{V_y}{V_x})\\ \\ \theta=\tan^{-1}(\frac{-504.65}{35.35})\\ \\ \theta=-86° \end{gathered}

The angle -86° is equivalent to -86 + 360 = 274°.

Therefore the correct option is b.

8 0
2 years ago
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