Step-by-step explanation:
If PQRS is a quadrilateral inscribed in a circle, then the opposite angles of the quadrilateral are <u>supplementary</u><u>.</u>
y + 68° = 180° { being opposite angles of cyclic quadrilateral }
y = 180° - 68°
y = 112°
x + 82° = 180° { being opposite angles of cyclic quadrilateral }
x = 180° - 82°
x = 98°
Hope it will help :)❤
Answer:
I would go with c.
Step-by-step explanation:
Hope this helped!
Answer:
∠RST = 40°
Explanation:
We are given that:
SQ bisects angle RST.
This means that:
∠QST = ∠QSR
2x = 3x - 10
10 = 3x - 2x
x = 10
Therefore:
∠QST = 2x = 2(10) = 20°
∠QSR = 3x - 10 = 3(10) - 10 = 30 - 10 = 20°
Note that both angles are equal.
Now, we can get ∠RST as follows:
∠RST = ∠QST + ∠QSR
∠RST = 20 + 20 = 40°
Hope this helps :)
Hello,
P(x)=x^3+2x²-23x-60
P(-4)=(-4)^3+2*(-4)²-23*(-4)-60=0
P(-3)=(-3)^4+2*(-3)²-23*(-3)-60=0
P(5)=5^3+2*5²-23*5-60=0
Zeros are -4,-3,5
2^2/-5=-4/5
-(5/4)^3=-125/64
Hope this helps!!
