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ad-work [718]
3 years ago
9

Count one of four equal parts

Mathematics
1 answer:
Sedbober [7]3 years ago
5 0

Answer:

i think this is it 1/4 but need more context

Hope this helps :)

Step-by-step explanation:

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The perimeter of a rectangular garden is $_64$_ centimeters. The length of the garden is three times the width. Find the length
CaHeK987 [17]

Answer:

length is 24 cm, width is 8 cm

Step-by-step explanation:

3 0
3 years ago
Type a digit that makes this statement true. NO LINKS!<br><br><br>3,737,<br><br>64 is divisible by 8
Pani-rosa [81]

Answer:

8

Step-by-step explanation:

3737648 / 8 = 467206

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A rain storm came through Clifton park and it was accumulating 2/3 inches of rain/hour. How many inches of rain would fall in 6
nlexa [21]

4 inches of rain would fall in 6 hours

<h3><u>Solution:</u></h3>

Given that, A rain storm came through Clifton park  

And it was accumulating \frac{2}{3} inches of rain/hour

So amount of rain accumulated in 1 hour = \frac{2}{3}

Thus amount of rain accumulated in six hours is calculated by multiplying the amount of water accumulating per hour and 6

Amount of water accumulated in 6 hours = Amount of water accumulated in 1 hour \times 6

\text { Amount of water accumaulated in 6 hours }=\frac{2}{3} \times 6=4

<em><u>Another way:</u></em>

Let "n" be the amount of rain accumulated in 6 hours

1 hour ⇒ \frac{2}{3} rain accumulated

6 hours ⇒ "n"

By cross multiplication, we get

6 \times \frac{2}{3} = 1 \times n\\\\n = \frac{2}{3} \times 6 = 4

Hence, 4 inches of rain would fall in 6 hours.

4 0
3 years ago
How many sides do 1980 have
mel-nik [20]

Answer:

13 sides

Step-by-step explanation:

1980 = (n − 2)×180         Formula for number of sides

n − 2 = 1980/180            Divide both sides by 180

n - 2 = 11            

  + 2   + 2                       Add 2 to both sides

n = 13

8 0
3 years ago
Jefferson wants to work at least 25hours this week. If he has already worked 22 hours, how many hours does he need to work on Sa
AnnyKZ [126]
The answer is 3 hours
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3 years ago
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