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2 years ago

14

Y – 84 = -11(x – 6) What is the point and slope

1 answer:

ale4655 [162]2 years ago

4 0

Answer:

The slope should be -11 and the points should be (6,84)

Step-by-step explanation:

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Jimmy invests $15,000 in an account that pays 8.90% compounded quarterly. How long (in years and months) will it take for his in

viktelen [127]

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22/15=(1.02225)^4t
log(22/15)=4tlog1.02225
(log(22/15)/4log1.02225)=t
(.16633/.038228)=t
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3 years ago

Can someone explain and answer

Gwar [14]

The answer is D. y = -2x + 20. This is because it has a negative slope (-2x). When a number in a slope-intercept equation has the variable (x), that determines the positive or negative association. If it is a positive slope, it travels up from left to right. If it is a negative slope, it travels down from left to right.

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2 years ago

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I need help i will mark brainiest

o-na [289]

Step-by-step explanation:

option D

16+ 125/ 6= 141/6 = 47 / 2 = 23.5

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2 years ago

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Find the vertex of the function given below.<br><br> y= x2 - 6x +1

Helga [31]

Answer:

V( 3, -8 )

Step-by-step explanation:

Parable equation is of the form:

( x - h )² = 4p*(y - k)

In that expression, vertex has coordinates V ( h, k )

Then all we have to do is transform the given equation

y = x² - 6x + 1 or x² - 6x = y - 1 (1)

We can get a perfect square trinomial in the first member of the equation according to:

x² - 6x = ( x - 3 )² - 9

(x - 3 )² = x² - 6x + 9

By substitution en equation (1)

( x - 3 )² - 9 = y - 1

( x - 3 )² = y -1 + 9

( x - 3 )² = y + 8

( x - 3 )² = (y + 8 )

Then vertex coordinates are

V( 3 , -8)

3 0

2 years ago

A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin

riadik2000 [5.3K]

Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

$p=\frac{x}{n}$

$p=\frac{80}{100}$

$p=0.8$

Now we define hypothesis,

Null hypothesis $H_0$ : candidate A is significantly greater than 75%.

Alternative hypothesis $H_1$ : candidate A is not significantly greater than 75%.

Level of significance $\alpha=0.05$

Applying test statistic Z -proportion,

$Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}$

Where, $\widehat{p}=80\%=0.80$ and $p=75%=0.75$

Substitute the values,

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}$

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}$

$Z=\frac{0.05}{0.0433}$

$Z=1.1547$

The p-value is

$P(Z>1.1547)=1-P(Z$

$P(Z>1.1547)=1-0.8789$

$P(Z>1.1547)=0.1241$

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

7 0

3 years ago