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3 years ago

Y – 84 = -11(x – 6) What is the point and slope

Mathematics

1 answer:

ale4655 [162]3 years ago

4 0

Answer:

The slope should be -11 and the points should be (6,84)

Step-by-step explanation:

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A manager wants to determine if an employee training program has increased her employees’ customer satisfaction ratings. She ran

lubasha [3.4K]

Answer:

Step-by-step explanation:

The answer should be A
I hope that's ok if I am wrong pls correct me

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2 years ago

Heather and her family are going to the grand opening of a new amusement park. There is a special price on tickets this weekend.

Likurg_2 [28]

56 + 16.80 = 72.80!!!!!!!!!!!!!

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3 years ago

Read 2 more answers

A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the

iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

$Event\ 1 = \{1,2,3,4,5,6\}$

Next, we list out the sample space of F

$Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\$

$6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}$

In (1): the sample space of E is:

$E = \{1\}$

So:

$P(E) = \frac{n(E)}{n(Event\ 1)}$

$P(E) = \frac{1}{6}$

In (2): the sample space of F is:

$F = \{5,5,5,5\}$

So:

$P(F) = \frac{n(F)}{n(Event\ 2)}$

$P(F) =\frac{4}{36}$

$P(F) =\frac{1}{9}$

For E and F to be independent:

$P(E\ and\ F) = P(E) * P(F)$

Substitute values for P(E) and P(F)

This gives:

$P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}$

$P(E\ and\ F) = \frac{1}{54}$

However, the actual value of P(E and F) is 0.

This is so because $E = \{1\}$ and $F = \{5,5,5,5\}$ have 0 common elements:

So:

$P(E\ and\ F) = 0$

Compare $P(E\ and\ F) = \frac{1}{54}$ and $P(E\ and\ F) = 0$ .

These values are not equal.

Hence: the two events are not independent

6 0

3 years ago

A particular fruit's weights are normally distributed, with a mean of 406 grams and a standard deviation of 27 grams.The heavies

Tom [10]

Given

mean of 406 grams and a standard deviation of 27 grams.

Find

The heaviest 14% of fruits weigh more than how many grams?

Explanation

given

mean = 406 gms

standard deviation = 27 gms

using standard normal table ,

$\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}$

Final Answer

Therefore , The heaviest 14% of fruits weigh more than 435.16 gms

8 0

1 year ago

Help me please I need help on this question!!!!!

Liono4ka [1.6K]

The answer is b I think

5 0

3 years ago