All categories

4 years ago

Slove this for me please

Mathematics

1 answer:

Allushta [10]4 years ago

7 0

Answer:v dfvdfv,mdsnv,.dcmv.dv

cdvmncm n nmej,vbcn Step-by-step explanation:

You might be interested in

What is 16 divided by X^2 equals 8 divided by X + 6?

zaharov [31]

Solve: $\frac{16}{x^{2}} = \frac{8}{x + 6}$

$\frac{16}{x^{2}} = \frac{8}{x + 6}$

$\text{Cross multiply: } 16(x + 6) = 8x^{2}$
$\text{Simplify: } 2(x + 6) = x^{2}$
$\text{Expand: } 2x + 12 = x^{2}$

$\text{Solve for x: } x^{2} - 2x - 12 = 0$

$\text{Use the quadratic equation: } x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}$
$x = \frac{2 \pm \sqrt{4 + 48}}{2}$
$x = \frac{2 \pm \sqrt{52}}{2}$
$x = \frac{2 \pm \sqrt{13 \cdot 4}}{2}$

$x = \frac{2 \pm 2\sqrt{13}}{2}$
$\therefore x = 1 \pm \sqrt{13}$

7 0

3 years ago

Please help! i cant solve it

3241004551 [841]

a ≈ 5.2, B ≈ 50°, C ≈ 95°

Solution:

Given data:

A = 35°, b = 7, c = 9

Using cosine law,

$a^{2}=b^{2}+c^{2}-2 b c \cos A$

$a^{2}=7^{2}+9^{2}-2 (7)(9) \cos 35^\circ$

$a^{2}=49+81-126 (0.82)$

$a^{2}=26.68$

Taking square root on both sides.

a ≈ 5.2

Using sine law,

$$\frac{\sin A}{a} =\frac{\sin B}{b}$

$$\frac{\sin 35^\circ}{5.2} =\frac{\sin B}{7}$

Multiply by 7 on both sides.

$$\frac{0.5735}{5.2}\times 7 =\sin B$

Switch the sides.

Sin B = 0.772

$B=\sin^{-1}0.772$

B ≈ 50°

Sum of all the angles of a triangle = 180°

A + B + C = 180°

35° + 50° + C = 180°

85° + C = 180°

C = 180° - 85°

C = 95°

Hence a ≈ 5.2, B ≈ 50°, C ≈ 95°.

4 0

3 years ago

Please someone help :) thanks ; )

sammy [17]

X/4 = 21
x = 21 · 4
x = 84

6 0

4 years ago

Read 2 more answers

3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie

allsm [11]

Answer:

<em>The building is 61.5 m tall</em>

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

h = height of the building

a, b = internal angles of each triangle

x = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

$\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}$

$\displaystyle \tan 53^\circ=\frac{150-x}{h}$

$\displaystyle \tan 48^\circ=\frac{x}{h}$

From the last equation:

$x=h.\tan 48^\circ$

Substituting into the first equation:

$\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}$

Operating on the right side:

$\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ$

Rearranging:

$\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}$

Solving for h:

$\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}$

Calculating:

h = 61.5 m

The building is 61.5 m tall

5 0

3 years ago

Part A

Zarrin [17]

Answer:

Step-by-step explanation: The answer is 6.8 add 5.2+ 1.6= 6.8 that is the distance. The answer is positive because it is distance and distance positive ." Distance is always positive and is equal to the absolute value, or magnitude, of the displacement. " Hope this helps :)

4 0

3 years ago

Slove this for me please​

Slove this for me please