Answer:
dont have question
Step-by-step explanation:
<span>F for Frank, A or Alice.
F(initial)=1.95 inches
A(initial)=1.50 inches
Frank's equation at .25 inches per year and t representing year variable.
F=1.95+.25t
Alice's equation at .40 inches per year and t representing year variable.
A=1.5+.40t
To figure out how old they will be when their beaks are the same lengths set the equations equal to eachother as the equations are length.
1.95+.25t=1.5+.40t
.45=.15t
t=3 years</span>
B+c+(c-b)+(b-c). That is your expression. b 11 c 16
First, let's convert the variables to real numbers: 11+16+(16-11)+(11-16)
Now, let's solve that equation. 11+16+5+(-5)
5+(-5) cancels out, so all we have left is: 27
That is your perimeter.
Answer:
1. 8/3
2. 1/7
3. 1/12
4. 1/27
Step-by-step explanation:
1. 3/8 * m = 1
Multiply by 8/3
8/3 * 3/8 m = 1* 8/3
m = 8/3
2. 7 * m = 1
Divide by 7
7*m /7 = 1/7
m = 1/7
3. 3 ÷m = 36
Multiply by m
3 ÷m * m = 36*m
3 = 36*m
Divide by 36
3/36 = 36*m/26
1/12 = m
4. 4/9 ÷m = 12
Multiply by m
4/9 ÷m * m = 12*m
4/9 = 12*m
Multiply by 1/12
4/9 *1/12 = 12*m * 1/12
4/12 *1/9 = m
1/3*1/9 =m
1/27
The depth of the swimming pool that is filled to the top is; 4 m
<h3>Snell's Law</h3>
I have attached a schematic diagram showing this question.
The correct width of the pool is 4 meters. Thus; w = 4 m
Incident Angle; θ₁ = 20°
A right angle is 90° and so the angle θ₂ is calculated from;
θ₂ = 90° - θ₁
θ₂ = 90° - 20°
θ₂ = 70°
We can use snell's law formula to find θ₃.
Thus;
n₁sinθ₂ = n₂sinθ₃
where;
n₁ is refractive index of air = 1
n₂ is refractive index of water = 1.33
Thus;
1*sin 70 = 1.33*sin θ₃
sin θ₃ = (sin 70)/1.33
Solving this gives;
θ₃ = 44.95°
By usage of trigonometric ratios we can find the depth of the pool using;
w/d = tan θ₃
Thus;
d = w/(tan θ₃)
d = 4/(tan 44.95)
d ≈ 4 m
Read more about Snell's Law at; brainly.com/question/10112549
