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valentinak56 [21]
2 years ago
15

Find the area of circle o if DCBO is a rectangle and DB measure 10 units

Mathematics
2 answers:
GREYUIT [131]2 years ago
5 0

Answer:

  314.2 square units

Step-by-step explanation:

The diagonals of a rectangle are the same length, so segment OC is the same length as segment DB: 10 units. OC is a radius of the circle, which means the circle's radius is 10 units.

The area of a circle is given by ...

  A = πr²

  A = π(10 units)² = 100π units²

  A ≈ 314.2 units²

The area of circle O is about 314.2 square units.

Dmitrij [34]2 years ago
3 0

Answer:

100\pi

Step-by-step explanation:

Step 1: Identity the radius.

Since O is the center of the circle, and C and E lie on the circumference, OC and OE are the radii of the circle and thus,

OC=OE.

Step 2: Consider the rectangle.

All diagonals in a rectangle are congruent so this means

DB= OC ( OC is also a diagonal).

Thus, OC= 10 units.

Step 3: Analyze

So this means OE is also 10 units as well.

Since we know the length of the radius, Use the area of circle,

\pi {r}^{2}

\pi( {10}^{2} ) = 100\pi

So the area of a circle is 100 pi.

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Step-by-step explanation:

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4 years ago
Calc I optimization problem, Please see attachment!
stellarik [79]
<h3>Answer:  14 feet</h3>

=======================================================

Explanation:

Let C be the corner point.

x = distance from P to C

That makes segment AP to be 70-x feet long

Focus on the right triangle PBC. Use the pythagorean theorem to find the hypotenuse PB.

a^2 + b^2 = c^2\\\\c = \sqrt{a^2 + b^2}\\\\PB = \sqrt{(PC)^2 + (CB)^2}\\\\PB = \sqrt{x^2 + 90^2}\\\\PB = \sqrt{x^2 + 8100}\\\\

If we knew what x was, then we could find a numeric value for PB.

---------------------

It costs $28 per foot to run cable along the ground. This is the portion from A to P. So it costs 28(70-x) dollars to run that portion of cable above ground. Simply multiply the cost per foot by the number of feet.

Similarly, the cost from P to B is 53\sqrt{x^2+8100} since it costs $53 per foot to have it run underground.

The total cost is therefore 28(70-x) + 53\sqrt{x^2 + 8100}

The derivative of this will help determine when the cost is minimized.

Type that function into GeoGebra and have it compute the derivative.

You should find that the x intercept of the derivative curve is exactly x = 56

If x = 56, then 70-x = 70-56 = 14

This means AP = 14 feet is the amount of cable to run along main street.

This also leads to PB = \sqrt{x^2 + 8100} = \sqrt{56^2 + 8100} = 106

The total length of the wire is 14+106 = 120 feet

It costs $28 per foot along the 14 ft section, so 28*14 = 392 dollars is the cost for this section.

It costs $53 per foot along the 106 ft section, so 53*106 = 5618 dollars is the cost for this other section.

The total min cost is 392+5618 = 6010 dollars

------------------

Side note: You could do all this without a calculator to compute the derivative and use algebra to end up with x = 56. However, I think the use of technology is beneficial because it's fast/efficient. In real world settings, you won't be likely to pull out pencil/paper to get things done. The modern world relies on computers. It's refreshing to see that your teacher encourages the use of technology.

Let me know if you need me to go over the algebraic steps and I'll update my answer.

3 0
3 years ago
If the area A of a triangle is 72, and the height h is equal to the length of the base b, what is the length of the base?
alexgriva [62]

Answer:

option B

Step-by-step explanation:

let the height=x

base=x

Area=½bh

72=½x•x

72×2=x²

144=x²

x=√144=12

5 0
3 years ago
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$34 is the answer. I’m glad I helped
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