Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
er level when the water is 6 m deep. (1 L = 1000cm^3)
1 answer:
Answer:

For this case we know that
represent the radius,
the height and the rate given is:


And replacing we got:

And that represent 
Step-by-step explanation:
For a tank similar to a cylinder the volume is given by:

For this case we know that
represent the radius,
the height and the rate given is:

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

And solving for
we got:

We need to convert the rate given into m^3/min and we got:

And replacing we got:

And that represent 
You might be interested in
1. 4n + 28
2. 30-10x
3. 3m+3n
4. 8+2j
Answer: (x + 1) ( x + 4)
Step-by-step explanation:
Answer:
y=6,5,4,3 are value for y
I believe that the number of miles traveled would be 8. This is because you would subtract $5.00 from the $13.80 and then divided by $1.10.
The answer is 10 - 3√2
:) hope this helps!