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3 years ago

I NEED HELP! PLEASE!

Mathematics

2 answers:

3241004551 [841]3 years ago

7 0

Answer:

1. -16

2. 1 (12 x 0 = 0 but its not the right)

3. 43

4.80

5. 5 4 (5 x 5 x 5 x 5 = 625)

IgorC [24]3 years ago

5 0

Answer:-16 and 1

Step-by-step explanation:

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What is this answer????

serious [3.7K]

Answer:

im pretty sure its c

Step-by-step explanation:

5 0

3 years ago

What are the solutions to the equation

frosja888 [35]

Answer:

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

3 years ago

20 is 80 percent of what number?

ziro4ka [17]

Answer: 100

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which line contains the point (1,-3)

Rzqust [24]

There are infinitely many lines that have the point (1,-3).

A line can be expressed as:

y=mx+b, where m=slope and b=y-intercept..

Our only restriction is that it passes through (1,-3) so

-3=1m+b

So as long as the sum of the slope and the y-intercept is equal to -3, that is one of the infinite number of lines that passes through (1, -3)

So we could also say b=-3-m then our infinite lines are:

y=mx-3-m, now any real value of m creates a specific line that passes through the point. ie the first few are

y=x-4, y=2x-5, y=3x-6 or even y=x√2-3-√2

4 0

3 years ago

A local movie theater charges customers $11 to watch one movie if you pay a membership fee $40 per month you pay only three doll

Nikolay [14]

Answer:

You would have to watch 30 movies.

Step-by-step explanation:

13 x 3 =39

3 0

3 years ago