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Elodia [21]
3 years ago
11

Create a conditional expression that evaluates to string "negative" if userVal is less than 0, and "non-negative" otherwise. Ex:

If userVal is -9, out
Computers and Technology
1 answer:
ArbitrLikvidat [17]3 years ago
8 0

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 

 System.out.print("Enter a number: ");

 int userVal = input.nextInt();

 

 String aString;

 if(userVal < 0)

     aString = "negative";

 else

     aString = "non-negative";

     

 System.out.println(aString);

}

}

Explanation:

Ask the user to enter a number and set it to userVal

Check the value of userVal. If it is smaller than 0, set the string as "negative". If it is not, set it as "non-negative"

Print the string

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Program:
Mkey [24]

Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

print('s - Shorten spaces')

print('q - Quit\n')

#getting choice

choice=input('Choose an option: ').lower()

#identifying choice

if choice=='c':

#displaying number of non white space chars in input_str

print('Number of non-whitespace characters:',get_num_of_non_WS_characters(input_str))

elif choice=='w':

#displaying number of words in input_str

print('Number of words:',get_num_of_words(input_str))

elif choice=='f':

#fixing capitalization and getting updated string and count of values capitalized

input_str,count=fix_capilization(input_str)

#displaying results

print('Number of letters capitalized:',count)

print('Edited text:',input_str)

elif choice=='r':

#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

print('Edited text:', input_str)

elif choice=='s':

#shortening spaces and displaying updated text

input_str = shorten_space(input_str)

print('Edited text:', input_str)

#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

#i is not a space

count+=1

return count

#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

words=input_str.split(' ')

count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

return count

#method to fix capitalization and return updated string and count of letters updated

def fix_capilization(input_str):

count=0

beginning=True #starting letter should be capitalized

result=''

for i in input_str:

if beginning and i.isalpha():

#start of a sentence and i is alphabetic

if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

count+=1

result+=i

#not start of a sentence

beginning=False

elif i in '?.!':

#i is either ? or . or !, next letter should be capitalized

beginning=True

result+=i

else:

#any other character

result+=i

return result,count

#method to replace exclamation and semicolons with period and comma respectively

def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

if i=='!':

i='.'

exclamationCount+=1

elif i==';':

i=','

semicolonCount+=1

result+=i

print('Punctuation replaced')

#displaying replaced values counts

print('exclamationCount:',exclamationCount)

print('semicolonCount:',semicolonCount)

return result

#removes all double or more spaces in input_str

def shorten_space(input_str):

input_str=input_str.strip()

result=''

prev=None

for i in input_str:

if prev==None:

result+=i

elif i==' ':

if prev != ' ':

result+=i

else:

result+=i

prev=i

return result

if __name__ == '__main__':

#getting input, printing it

input_str=input('Enter a sample text:\n')

print('\nYou entered:',input_str)

choice=' '

#looping until choice becomes q

while choice!='q':

choice,input_str=print_menu(input_str)

7 0
3 years ago
For this assignment: Analyze and describe the network infrastructure. Describe and explain the various policies that will be nee
mamaluj [8]

Answer:

Explanation:

The Network infrastructure shown here are LAN and WAN. Wired and wireless communications.

The Various policies are:

1. Group related items together, for instance, grouping all Windows servers, into one virtual LAN (VLAN). Other asset groups might include infrastructure (routers, switches, VPNs and VoIP) in one VLAN and security assets (IDS, firewalls, web filters and scanners) may be grouped in another.

2. In general, it is good to adopt a default deny access posture for each VLAN.

3. Network segmentation is a very significant, long-term project, but each step along the way increases security. Log all traffic between segments to determine what is normal and needed for effective functioning.

4. Network segmentation is undeniably and unquestionably an effective component in a defense in depth strategy. Organizations that implement it must be prepared to manage scores of firewalls, switches and routers, each with hundreds of rules, all of which may be affected by the network segmentation process and potentially by updates and changes, even after it is in place.

5. Contribute to a secure WAN environment for all connected departments, offices,

agencies, boards, and commissions

6. Provide a uniform security framework to secure the integrity, confidentiality, and availability of info and info systems, at the WAN level.

7. Provide, in balance with operational requirements, legislative requirements, and information sharing agreements, the minimum WAN security requirements.

8. Raise awareness of information and information technology security needs for all users of the WAN by providing the security principles, requirements.

9. Define the clear roles and responsibilities of all users of the WAN, particularly WAN security staff.

* Vulnerabilities and exposures

1. Data requiring special protection such as credit card numbers that need to comply with PCI-DSS or patient information that is subject to HIPAA should be isolated from other data and put in their own VLANs.

2. Your aim is to limit access to sensitive information to those who need it within the organization and to create roadblocks to stop or slow intruders, who may have broken through one layer of security, from doing further damage.

3. Network segmentation is not a “set and forget” undertaking. The network access policy, defined in firewalls, routers and related devices, changes constantly to cater to new business requirements. Ensure that new changes do not violate your segmentation strategy requires a good degree of visibility and automation.

4. Reducing internal breaches and the infiltration of malicious software(malware). This

internal defense requires significant involvement with individual devices

on a network, which creates greater overhead on network administrators.

*Risks

1. Malicious software, also known as malware,makes its way onto a network through

employees, contractors and visitors. Personal laptops, wireless gadgets,

and of course the USB flash drives, all these provide excellent vectors through which

malware can enter the workplace.

2. Hackers, worms, spammers and other security dangers of the Internet via LAN.

3. The various vulnerabilities on your network represent potential costs — time, money and assets — to your library. These costs, along with the chance someone will exploit these vulnerabilities, help determine the level of risk involved.

4. Since the cost of adding another Internet connection, increasing the speed of the current connection or purchasing complex network monitoring equipment might be too prohibitive, the library has a higher tolerance for a periodically slow Internet connection.

5. External flash drives and other media are also concern when those enters the network.

6. The lost or stolen handheld device poses some serious risks if not incorporated into your network security policy. Such devices are often capable of being formatted of all company content remotely in the case of theft or robbery.

*Security measurements:

1. Address Resolution

Protocol (ARP) spoofing, Denial of Service (DoS) attacks such as Tear Drop

or Ping of Death.

2. In addition, network administrators can form a policy whereby network

users are required to install and maintain anti-malware scanners in their devices.

3. Many tools exist to check the existing security state of your network. The Microsoft Baseline Security Analyzer, Nmap .

4. Risk assessment is a combination of both quantifying (the cost of the threat) and qualifying (the odds of the attack).

5. Firewalls.

6. Antivirus systems.

7. Intrusion-detection systems (Host-based IDS,Network-based IDS)

8. Port scanners.

9. Network sniffers.

10. A vulnerability scanner is like a port scanner on steroids.

*Unnecessary Ports

1. It is not easy to say which ports exactly but we should know that the service ports which are open among 65,535 ports and although not exactly sure what service is running , it is safer to check the port and close it as "A Closed Port is a Safe Port".

7 0
3 years ago
I need help with this question. asap please
marissa [1.9K]

Answer:

what are you talking about

Explanation:

can you help me with my question

8 0
2 years ago
Most colleges require blank years of foriegn language for admission
Sladkaya [172]

They require about 4 years of foreign language if you want to learn more afterwards then it is another 2 years or 3.

3 0
3 years ago
What is a benefit of using client/server network?
ANTONII [103]

The answer is centralization

A client-server network is a server which acts as one powerful computer that provides information to other sub-ordinate workstations called the client. The biggest benefit of this setup is centralization or the central management of the server. Only a single server functions as a host that all clients request and use. Having a single centrally managed server is cost effective and is easily manageable. This centralized control can also be used to deploy processes, allocate user resources and delegate access permissions easily and effectively.

3 0
3 years ago
Read 2 more answers
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