Answer:
FOR REGULAR PYRAMID with those dimension.
L.A = 96
FOR HEXAGONAL PYRAMID with those dimension
L.A = 171.71
Step-by-step explanation:
Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.
Hence I solved for both:
FOR REGULAR PYRAMID
Lateral Area (L.A) = 1/2* p * l
Where p = Perimeter of base
P = 4s
P = 4 * 6
P = 24cm
l = slanted height
l = 8cm
L.A = 1/2 * 24 * 8
L.A = 1/2 ( 192)
L.A = 96cm ^ 2
FOR AN HEXAGONAL PYRAMID
Lateral Area = 3a √ h^2 + (3a^2) / 4
Where:
a = Base Edge = 6
h = Height = 8
L.A = 3*6 √ 8^2 + ( 3*6^2) / 4
L.A = 18 √ 64 + ( 3 * 36) / 4
L.A = 18 √ 64 + 108/4
L.A = 18 √ 64+27
L.A = 18 √ 91
L.A = 18 * 9.539
L.A = 171.71
The dimensions given are 8 feet length and 4 inches height. The volume of the rectangular portion is $58.07 divided by $98 per cubic yard equal to 0.59255 cubic yards. 8 feet is equal to 8/3 yards and 4 inches is equal to 1/9 yards. Hence the width is equal to 0.59255 cubic yards / (8/3)/(1/9) yards2 equal to 2 yards
2x + 8 = 50
Subtract 8 from both sides
2x = 42
Divide both by 2
x = 21
I believe the answer is B. 4.4
