They made a profit of $1,430. Simple math. Multiply 8*220 to see how much they spent. Then multiply 14.50*220 to see how much they received from all the sweatshirts. Lastly, subtract how much they spend versus how much the made.<span />
Answer:
90
Step-by-step explanation:
The sum of squares of the deviation from mean=sum(x-xbar)²=?
x
12
6
15
9
18
12
xbar=sumx/n
xbar=(12+6+15+9+18+12)/6=72/6=12
x x-xbar (x-xbar)²
12 12-12=0 0
6 6-12=-6 36
15 15-12=3 9
9 9-12=-3 9
18 18-12=6 36
12 12-12=0 0
sum(x-xbar)²=0+36+9+9+36+0=90
So, the sum of squares of the deviations from the mean is 90.
The area in which the right angle was at before. the angle nor the triangle changes
Answer: 1. 7
2. 100
3. 193.8
4. 0.8
5. 90.6
Step-by-step explanation:
1. Given the data 9,3,10,12,4,5,12,2
For finding the median we arrange it in ascending order
2,3,4,5,9, 10,12,12
Since the no of observations are even
∴ median =
= 
=
=7
i.e. Median =7
2. Given the data
23, 95,100,23,100,100
Since the no 100 is repeated thrice i.e. the maximum no of times
∴ Mode=100
3.
Given the data
108, 305,252,113, 191
Mean=
=
=193.8
4. Money spent in the first week
= $11.52, $6.48, $5.99, $14.00, and $9.50
Total for the first week
=11.52+6.48+5.99+14.00+9.50
=$47.49
Now she spent $4 more in the second week
i.e.$47.49+4
=51.49$
Increase in mean =
=0.8
5.
Given
2 students scored 100 each
9 students scored 95 each
10 students scored 90 each
3 students scored 80 each
1 student scored 70
Total score of students =
=2265
The average score
=
=90.6
Answer:
(1)
Multiplying by 3 both sides of the equality you get that

3u is in the Span of the vectors
.
(2)
That's not true, consider the following counter example.

is a linear combination of
but is NOT a linear combination of 
Step-by-step explanation:
(1)
As the hint indicates, you know that

Then, if you multiply both sides of the equality by 3, you get that

And that's it. 3u is in the Span of the vectors 
(2)
That's not true, consider the following counter example.

is a linear combination of
but is NOT a linear combination of 