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soldier1979 [14.2K]
3 years ago
8

Explain how you could estimate 22% of 78 to check if your answer is reasonable.

Mathematics
1 answer:
choli [55]3 years ago
5 0

you can find 10 percent by dividing 78 by 10 which is 7.8. Then you double that to find 20 percent. That will make you find 20 percent! close to 22

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The sixth grade class sold sweatshirts with their school logo to raise money for a field trip they bought 220 sweatshirts for $8
IRINA_888 [86]
They made a profit of $1,430. Simple math. Multiply 8*220 to see how much they spent. Then multiply 14.50*220 to see how much they received from all the sweatshirts. Lastly, subtract how much they spend versus how much the made.<span />
7 0
3 years ago
The data shows the total number of employee medical leave days taken for on-the-job accidents in the first six months of the yea
Inga [223]

Answer:

90

Step-by-step explanation:

The sum of squares of the deviation from mean=sum(x-xbar)²=?

x

12

6

15

9

18

12

xbar=sumx/n

xbar=(12+6+15+9+18+12)/6=72/6=12

x      x-xbar       (x-xbar)²

12      12-12=0     0

6       6-12=-6     36

15      15-12=3      9

9       9-12=-3       9

18      18-12=6      36

12      12-12=0      0

sum(x-xbar)²=0+36+9+9+36+0=90

So, the sum of squares of the deviations from the mean is 90.

3 0
3 years ago
If you rotate a right triangle, what feature of the triangle changes?
rusak2 [61]
The area in which the right angle was at before. the angle nor the triangle changes
7 0
3 years ago
1. What is the median of the data set?
Tamiku [17]

Answer: 1. 7

2. 100

3. 193.8

4. 0.8

5. 90.6

Step-by-step explanation:

1. Given the data  9,3,10,12,4,5,12,2

For finding the median we arrange it in ascending order

2,3,4,5,9, 10,12,12

Since the no of observations are even

∴ median =\frac{n/2 th term + (n/2 + 1)th term}{2}

= \frac{5+9}{2}

=\frac{14}{2}

=7

i.e. Median =7

2. Given the data

23, 95,100,23,100,100

Since the no 100 is repeated thrice i.e. the maximum no of times

∴ Mode=100

3.

Given the data

108, 305,252,113, 191

Mean=\frac{108+305+252+113+191}{5}

=\frac{969}{5}

=193.8

4. Money spent in the first week

= $11.52, $6.48, $5.99, $14.00, and $9.50

Total for the first week

=11.52+6.48+5.99+14.00+9.50

=$47.49

Now she spent $4 more in the second week

i.e.$47.49+4

=51.49$

Increase in mean =\frac{4}{5}

=0.8

5.

Given

2 students scored 100 each

9 students scored 95 each

10 students scored 90 each

3 students scored 80 each

1 student scored 70

Total score of students =2\times100+ 9\times 95+10\times90+3\times80+70\times1

=2265

The average score

=\frac{2265}{25}

=90.6

8 0
3 years ago
(1) Let {v1,v2,v3} be a set of vectors in Rn . If u is Span {v1,v2,v3}, show that 3u is in Span {v1,v2,v3}.
Evgesh-ka [11]

Answer:

(1)

Multiplying by 3 both sides of the equality you get that

3u = 3c_1v_1+3c_2v_2+3c_3v_3

3u  is in the Span of the vectors \{v_1,v_2,v_3\}.

(2)

That's not true, consider the following counter example.

v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)

u is a linear combination of v_1,v_2,v_3 but is NOT a linear combination of v_1,v_2,v_3,v_4.

Step-by-step explanation:

(1)

As the hint indicates, you know that

u = c_1 v_1 + c_2v_2+c_3v_3

Then, if you multiply both sides of the equality by 3, you get that

3u = 3c_1v_1+3c_2v_2+3c_3v_3

And that's it. 3u  is in the Span of the vectors \{v_1,v_2,v_3\}

(2)

That's not true, consider the following counter example.

v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)

u is a linear combination of v_1,v_2,v_3 but is NOT a linear combination of v_1,v_2,v_3,v_4.

4 0
3 years ago
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