7q² - 28 = 0
+ 28 + 28
7q² = 28
7 7
q² = 4
q = ±4
q = 4 or q = -4
Solution Set: {±4} and {q|q = 4 or q = -4}
Evaluate 2(x + 1) - 3 when x = 6.
First, plug in x value.
2(6 + 1) -3 ParenthesisEMDAS
2(7) - 3 PEMultiplyDAS
14 - 3 PEMDASubtract
11 ←
Answer:
<u>Answer</u><u>:</u><u> </u><u>A</u><u>.</u><u> </u><u>-</u><u>3</u><u>2</u><u>.</u><u>7</u><u>5</u>

• f(n) are the values of the set
• n is the number of items

Answer:
y = 3x + 22
Step-by-step explanation:
y - 7 = 3(x+5)
Distribute,
y - 7 = 3x + 15.
Add 7 to both sides.
Final answer, y = 3x + 22.
Hope this helps!