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sammy [17]
3 years ago
6

A circle has an area of 40 square meters. Which answer is closest to the measure of its diameter?

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
8 0

Answer: The correct answer is 7.12 m.

Step-by-step explanation:

The expression for the area of the circle is as follows;

A=\pi r^{2}

Here, A is the area of the circle and r is the radius of the circle.

Calculate the radius of the circle.

A=\pi r^{2}

Put A= 40 square meter and \pi=3.14.

40=(3.14) r^{2}

r=3.56 m

The expression for the diameter is as follows;

d= 2r

Here, d is the diameter of the circle and r is the radius of the circle.

Put r= 3.56 m.

d= 2(3.56)

d= 7.12 m

Therefore, the closest answer to the measure of the diameter of the circle is 7.12 m.

Citrus2011 [14]3 years ago
3 0

Answer:

7.1

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
(x−3)÷9=11<br> help idk how to do this
Bess [88]

Answer:

102

Step-by-step explanation:

papa math will help you

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

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https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

Close Ad

Back to Algebra Calculator »

Share this page

Share URL:

https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

Close Ad

Back to Algebra Calculator »

Share this page

Share URL:

https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

6 0
3 years ago
Can someone help me
Lemur [1.5K]
Multiplying fractions is just multiplying the numerators together and the denominators together.

\sf\dfrac{4}{7}\times\dfrac{1}{4}\rightarrow\dfrac{4\times 1}{7\times 4}\rightarrow\dfrac{4}{28}\rightarrow\dfrac{1}{7}

\sf\dfrac{4}{7}\times\dfrac{1}{6}\rightarrow\dfrac{4\times 1}{7\times 6}\rightarrow\dfrac{4}{42}\rightarrow\dfrac{2}{21}

To find out which one is bigger, we need a common denominator. The LCM of 7 and 21 is 21, so convert the first fraction into a denominator of 21. 7 goes into 21 three times, multiply this to the numerator and denominator:

\sf\dfrac{1}{7}\rightarrow\dfrac{1\times 3}{7 \times 3}\rightarrow\dfrac{3}{21}

Now just compare the numerators to see which one is bigger.

\sf\dfrac{3}{21}>\dfrac{2}{21} therefore, \sf\dfrac{4}{7}\times\dfrac{1}{4}>\dfrac{4}{7}\times\dfrac{1}{6}
5 0
3 years ago
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