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alexandr402 [8]
3 years ago
15

HURRY PLEASE I NEED THIS SOON

Mathematics
2 answers:
otez555 [7]3 years ago
7 0

Answer:

option 4 and 6

Step-by-step explanation:

Volgvan3 years ago
7 0

Answer:

Option 4

I am sorry I only know 1

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1-22 teacher was no help
damaskus [11]
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2) -3,-2,-1,0,1,2,3,4,5,6,7
3)-3,-2,-1
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3 0
3 years ago
Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .
kogti [31]

Answer:

The family of all prime numbers such that a^{2} + b^{2} + c^{2} -1 is a perfect square is represented by the following solution:

a is an arbitrary prime number. (1)

b = \sqrt{1 + 2\cdot a \cdot c} (2)

c is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if (x+y)^{2} = x^{2} + 2\cdot x\cdot y  + y^{2}. From statement, we must fulfill the following identity:

a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}

By Associative and Commutative properties, we can reorganize the expression as follows:

a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2} (1)

Then, we have the following system of equations:

x = a (2)

(b^{2}-1) = 2\cdot x\cdot y (3)

y = c (4)

By (2) and (4) in (3), we have the following expression:

(b^{2} - 1) = 2\cdot a \cdot c

b^{2} = 1 + 2\cdot a \cdot c

b = \sqrt{1 + 2\cdot a\cdot c}

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, a, b, c > 1. If a, b and c are prime numbers, then  2\cdot a\cdot c must be an even composite number, which means that a and c can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.

In addition, b must be a natural number, which means that:

1 + 2\cdot a\cdot c \ge 4

2\cdot a \cdot c \ge 3

a\cdot c \ge \frac{3}{2}

But the lowest possible product made by two prime numbers is 2^{2} = 4. Hence, a\cdot c \ge 4.

The family of all prime numbers such that a^{2} + b^{2} + c^{2} -1 is a perfect square is represented by the following solution:

a is an arbitrary prime number. (1)

b = \sqrt{1 + 2\cdot a \cdot c} (2)

c is another arbitrary prime number. (3)

Example: a = 2, c = 2

b = \sqrt{1 + 2\cdot (2)\cdot (2)}

b = 3

4 0
3 years ago
Help me out. good points the image shows​
Sphinxa [80]
To start off with you need to get math-way it will help out
5 0
2 years ago
Read 2 more answers
Two fair dice are rolled 3 times and the sum of the numbers that come up is recorded. Find the probability of these events. a. T
alexandr402 [8]

Answer:

Step-by-step explanation:

Given that two fair dice are rolled 3 times and the sum of the numbers that come up is recorded.

a) The sum is 4 on each of the three rolls.

(1,3) (2,2) (3,1) HEnce for one throw prob = 3/36 =1/12

Prob for getting same sum 4 in 3 rolls = (\frac{1}{12} )^3

(since each trial is independent)

b) Prob sum =4 in exactly 2 rolls

= 3C2 (1/12)^2 (11/12)=\frac{33}{12^3}

5 0
2 years ago
Which problem could be solved by evaluating the expression 4×(−6)?
natima [27]
THat would be option c  Her cahnge in points would be 4 * -6 = -24.
4 0
2 years ago
Read 2 more answers
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