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ruslelena [56]
3 years ago
6

Sarah and Joe are seeking to join a gym. Sarah saw on television that Great Gym is offering membership at $19.50 per month, plus

a one-time registration
fee of $59. Joe plans to join Workout World because Workout World only charges $9.50 per month, plus a one-time registration fee of $149.

3. If Sarah decides to join Great Gym and Joe joins Workout World, who would pay less during the first month of membership? Show your work.
Mathematics
2 answers:
xenn [34]3 years ago
8 0
Sarah because if you add up the one time registration fee and the amount per month for one month it would be less than Joe's
Ghella [55]3 years ago
5 0
Sarah's fees:
$19.50 monthly fee PLUS
$59.00 registration fee
EQUALS
$$78.50

Joe's fees:
$9.50 monthly
PLUS
$149.00 registration
EQUALS
$158.50

So Sarah pays $80.00 less than Joe.
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Find the circumference of circle with a radius of 63mm. Use 22/7 for pi
GREYUIT [131]
The circumference of circle with a radius of 63mm is 395.84

I hope this helps!
3 0
3 years ago
Use the graph of f to describe the transformation that results in the graph of g. f(x) = log x; g(x) = 2logx + 6 A.) The graph o
Anastaziya [24]

Answer:

  A.)  The graph of g(x) is the graph of f(x) expanded vertically by a factor of 2, and translated 6 unit(s) up.

Step-by-step explanation:

For vertical expansion by a scale factor of k, the graph of f(x) is transformed to ...

  g(x) = k·f(x)

For translation up by k units, f(x) is transformed to ...

  g(x) = f(x) +k

___

Comparing the following ...

  f(x) = log(x)

  g(x) = 2·log(x) +6

We see that a multiplication factor and an addition factor have been applied. That means ...

  g(x) is f(x) expanded vertically by a factor of 2, and translated up 6 units.

6 0
3 years ago
Simplify. (Assume all variables represent positive real numbers). Leave answer in radical form.
Flauer [41]

Answer:

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

Step-by-step explanation:

Given

\sqrt{128a^{6}b^{13}}

Required

Solve

\sqrt{128a^{6}b^{13}}

The expression can be split to:

\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64 * 2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12 + 1}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12}} * \sqrt{b}

So, we have:

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{6/2} * b^{12/2} * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{3} * b^{6} * \sqrt{b}

Rewrite as:

\sqrt{128a^{6}b^{13}} = 8 * a^{3} * b^{6}* \sqrt{2}  * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

5 0
3 years ago
Which expressions are equivalent to 6^16? Check all that apply.
gayaneshka [121]

Answer: (6^-4)^-4 , (6^-2)^-8, (6^8)^2

Step-by-step explanation:

When there is a number with an exponent in a parenthesis raised to another exponent, you multiply the two exponents together. So, in this case we are looking for 2 exponents that give us a product of 16.

4 0
3 years ago
Please help look at attached image below need an answer asap
NNADVOKAT [17]

Answer: 46 degrees

Step-by-step explanation:

180 degrees in a triangle and the two 5 sides are congruent, making the other two angles congruent

180 - 88 = 92

92 / 2 = 46

8 0
3 years ago
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