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3 years ago

C. 25 D. 6 Geometry math question please help me

Mathematics

1 answer:

Sophie [7]3 years ago

3 0

Hello!

According to the dashes, you can see that the two separate triangles are congruent. Therefore, these two angles are congruent. We will solve below.

6n-10=50

We add 10 to both sides.

6n=60

Divide both sides by 6.

n=10

Therefore, our answer is A) 10.

I hope this helps!

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Find the? inverse, if it? exists, for the given matrix. [4 3] [3 6]

True [87]

Answer:

Therefore, the inverse of given matrix is

$=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}$

Step-by-step explanation:

The inverse of a square matrix $A$ is $A^{-1}$ such that

$A A^{-1}=I$ where I is the identity matrix.

Consider, $A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]$

$\mathrm{Matrix\:can\:only\:be\:inverted\:if\:it\:is\:non-singular,\:that\:is:}$

$\det \begin{pmatrix}4&3 \\3&6\end{pmatrix}\ne 0$

$\mathrm{Find\:2x2\:matrix\:inverse\:according\:to\:the\:formula}:\quad \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}^{-1}=\frac{1}{\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}}\begin{pmatrix}d\:&\:-b\:\\ -c\:&\:a\:\end{pmatrix}$

$=\frac{1}{\det \begin{pmatrix}4&3\\ 3&6\end{pmatrix}}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}$

$\mathrm{Find\:the\:matrix\:determinant\:according\:to\:formula}:\quad \det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}\:=\:ad-bc$

$4\cdot \:6-3\cdot \:3=15$

$=\frac{1}{15}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}$

$=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}$

Therefore, the inverse of given matrix is

$=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}$

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4 years ago

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ivolga24 [154]

Answer

It is 11/12

hope im not late i hope it helps

Step-by-step explanation:

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3 years ago

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alexandr402 [8]

Answer:

The required points are -

(-2,8), (7,5), (1,7)

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3 years ago

Help please :))

Marysya12 [62]

Answer:

See below

Step-by-step explanation:

The roots are:

3, 3, 2 - 3i, 2 + 3i (conjugate of 2 - 3i should be added) and the leading coefficient is - 5

The polynomial is:

-5(x - 3)² (x - [2 - 3i]) (x - [2 + 3i]) =
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3 years ago

The square of the sum of two consecutive positive even integers is 4048 more than the sum of the squares of these two numbers. F

Burka [1]

Answer:

The numbers are 44 and 46

Step-by-step explanation:

Let

x, x+2 ----> the two consecutive positive even integers

we know that

$(x+x+2)^{2} =4,048+x^{2} +(x+2)^{2} \\ \\(2x+2)^{2} =4,048+x^{2} +x^{2}+4x+4\\ \\4x^{2}+8x+4=2x^{2}+4x+4,052\\ \\2x^{2} +4x-4,048=0$

Solve the quadratic equation using a graphing calculator

The solution is x=44

see the attached figure

$x+2=44+2=46$

therefore

The numbers are 44 and 46

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3 years ago