For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
<h3>
Integers divisible by 3</h3>
The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.
<h3>Proof for the divisibility</h3>
111 = 1 + 1 + 1 = 3 (the sum is multiple of 3 = 3 x 1) (111/3 = 37)
222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2) (222/3 = 74)
213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2) (213/3 = 71)
27 = 2 + 7 = 9 (the sum is multiple of 3 = 3 x 3) (27/3 = 9)
Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
Learn more about divisibility here: brainly.com/question/9462805
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Answer:
3.14 mile-55=51.86 miles from the car and exit
i think i help.(sorry if it is not correct)
Step-by-step explanation:
Answer:
\10 of its starting number
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∨ i am very good at this
Step-by-step explanation:
Answer:
4x+4y
Step-by-step explanation:
Only like terms can be added together so the numbers with the variable x are added together and numbers with the variable y are added together.
The expression can no longer be simplified since it has no other ways to.
Answer:
i√17 ≈ 4.123106i
Step-by-step explanation:
The square root of a negative number is "i" times the square root of its absolute value. It is an imaginary number.
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i is generally the symbol used for √(-1). In some fields, such as electrical engineering, where i has a different meaning, the symbol j may be used instead.
