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enyata [817]
3 years ago
12

Eddie is practicing wind sprints during his summer break. He’s able to run 72 meters in 12 seconds. If d represents distance and

t represents time, which equation represents this proportional relationship?]
Mathematics
1 answer:
AnnZ [28]3 years ago
4 0
D is distance which is 72 meters
time represents seconds which is 12
so ratio is 12:72
reduce to get 1:6
time over distance would be 1/6
every second Eddie runs 6 meters
so t= d/6
or 6t=d
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Write the equation of the line that passes through the points (−7,0) and (6,−4).
Over [174]

Answer:

y=-4/13x-28/13

Step-by-step explanation:

m=y2-y1/x2-x1

m=-4-0/6-(-7)

m=-4-0/6+7

m=-4/13

y-y1=m(x-x1)

y-0=-4/13(x-(-7))

y-0=-4/13x-28/13

y=-4/13x-28/13

5 0
3 years ago
Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
Solve for g.
Y_Kistochka [10]

Answer:

g =6/5                           g=-5/2

Step-by-step explanation:

(5g − 6)(2g + 5) = 0

Using the zero product property

(5g − 6)  =0          (2g + 5) = 0

5g-6+6 =0+6             2g+5-5=0-5

5g =6                          2g =-5

5g/5 = 6/5                  2g/2 =-5/2

g =6/5                           g=-5/2

7 0
3 years ago
Write an equation in Slope-Intercept Form using the table below. ​
Veseljchak [2.6K]

Answer:

y = x + 46

Step-by-step explanation:

When writing an equation of a line, keep in mind that you always need the following information in order to determine the linear equation in slope-intercept form, y = mx + b:

1. 2 sets of ordered pairs (x, y)

2. Slope (m)

3. Y-intercept (b)

First, choose two pairs of coordinates to use for solving the slope of the line:

Let (x1, y1) = (0, 46)

(x2, y2) =  (1, 47)

User the following formula for slope

m = \frac{y2 - y1}{x2 - x1}

Plug in the values of the coordinates into the formula:m = \frac{y2 - y1}{x2 - x1} = \frac{47 - 46}{1 - 0} = \frac{1}{1} = 1

Therefore, the slope (m) = 1.

Next, we need the y-intercept, (b). The y-intercept is the y-coordinate of the point where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0. The y-coordinate of the point (0, 46) is the y-intercept. Therefore, b = 46.

Given the slope, m = 1, and y-intercept, b = 46, the linear equation in slope-intercept form is:

y = x + 46

Please mark my answers as the Brainliest if you find my explanations helpful :)

8 0
3 years ago
What are the zeros of the function <br> f(x)= x^2+7x−18?<br>  <br> Enter your answers in the boxes.
olga55 [171]
The zeros of the function are x=2,-9
5 0
3 years ago
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