Answer:
The new pressure of the gas is 15.40 kPa.
Explanation:
Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. Mathematically this law indicates that the quotient between pressure and temperature is constant:
On the other hand, Boyle's law says that the volume occupied by a certain gaseous mass at constant temperature is inversely proportional to the pressure. This law is expressed mathematically as:
P*V=k
Finally, Charles's law indicates that as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. Mathematically, this law says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
Studying an initial state 1 and a final state 2, it is fulfilled:
In this case:
- P1= 10 kPa
- V1= 200 L
- T1= 0 C= 273 K
- P2=?
- V2= 175 L
- T2= 95 C= 368 K
Replacing:
Solving:
P2= 15.40 kPa
<u><em>The new pressure of the gas is 15.40 kPa.</em></u>
Answer:
given , v = 300 km/hr; distance d = 1500 km; then time t = d/v = 1500/300 = 5 hrs
Explanation:
Try this option (shortly):
According to the 'law of consevation of pulse' the passenger in the smaller car receives greater energy then the one in the larger car.
Almost all the received energy is spent to injure the passenger in the smaller car. :(
Answer:-2.61 m/s
Explanation:
This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum must be equal to the final momentum :
(1)
Where:
(2)
(3)
is the mass of the first car
is the velocity of the first car, to the North
is the mass of the second car
is the mass of the second car, to the South
is the final velocity of both cars after the collision
(4)
Isolating :
(5)
(6)
Finally:
(7) This is the resulting velocity of the wreckage, to the south
Qs 1: Yes, there is a force, and distance, and they point in the same direction.
Qs 2: 420,000 J