Explanation:
<u>Using Equations of Motion</u> :
(1) v = u + at
24 = 6.5 + a * 210
<u>a (Acceleration) = 0.083 m/s^2 </u>
<u>(</u><u>2</u><u>)</u><u> </u> v^2 = u^2 + 2aS
S = 576 - 42.25 / 0.166
<u>S (Distance travelled) = 3215.3 m </u>
(Option A seems a typo since the answer is 3215.3 m)
Answer:
option C
Explanation:
The correct answer is option C
A light that transmits through n₂ travels t distance before reflection off the n₁ medium and again travels distance t before reaching the point from where it entered n₂ medium. Hence it travels 2 t distance more than the light that is reflected off n₂.
It( light entering n₂) also travels an additional distance equal to, half of the wavelength, when reflected off n₁ ( as n₁ is greater than n₂).
Wavelength in n₂ is =
Hence, path length difference = 
Answer:
Explanation:
The east vector is 10cos45 = 7.07 km
The north vector is 10sin45 - 10 = -2.93 km
The displacement magnitude is
d = √(7.07² + 2.93²) = 7.65... = 8 km
θ = arctan(-2.93/7.07) = -22.51... = 23° south of east.